Como foi a despedida do bilhete?

Katena32 [7]

Answer:

Usually, the relationship between mass and weight on Earth is highly proportional; objects that are a hundred times more massive than a one-liter bottle of soda almost always weigh a hundred times more—approximately 1,000 newtons, which is the weight one would expect on Earth from an object with a mass slightly greater ...

8 0

3 years ago

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A cord is attached to the box and run through a pulley directly above the box, so that the cord is vertical. The free end of the

Harman [31]

Answer:

The answer is given here would be a simplified equation, seeing as there are some missing variables in the question.

F1 = T- 46, 674.656 gm/s²

Explanation:

Note: Once we have the mass of the second object and/or acceleration of the cord, we can solve for the force of the ground acting on the box.

To calculate the force caused by gravity on the basic pulley system we use the following equation:

F2 = M2 x g; where g= gravitational acceleration (a constant equal to 9.8 m/s²). The mass M2 = 10.5 lb = 4762.72g

∴ F2 = 4762.72g x 9.8 m/s²

= 46, 674.656 gm/s² or 46, 674.656 N

But since this F2 is acting in a downlowrd direction, it would be negative.

Tension of the cord, T = Mass, x × acceleration. ( x is in the pulley diagram)

⇒ F1 = T - F2

F1 = T- 46, 674.656 gm/s²

4 0

3 years ago

Thomson is responsible for discovering that an atom containing _________

EastWind [94]

protons, neutrons, and electrons.

6 0

3 years ago

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Astronomers discover an exoplanet, a planet obriting a star other than the Sun, that has an orbital period of 3.27 Earth years i

Naddik [55]

Answer:

r = 3.787 10¹¹ m

Explanation:

We can solve this exercise using Newton's second law, where force is the force of universal attraction and centripetal acceleration

F = ma

G m M / r² = m a

The centripetal acceleration is given by

a = v² / r

For the case of an orbit the speed circulates (velocity module is constant), let's use the relationship

v = d / t

The distance traveled Esla orbits, in a circle the distance is

d = 2 π r

Time in time to complete the orbit, called period

v = 2π r / T

Let's replace

G m M / r² = m a

G M / r² = (2π r / T)² / r

G M / r² = 4π² r / T²

G M T² = 4π² r3

r = ∛ (G M T² / 4π²)

Let's reduce the magnitudes to the SI system

T = 3.27 and (365 d / 1 y) (24 h / 1 day) (3600s / 1h)

T = 1.03 10⁸ s

Let's calculate

r = ∛[6.67 10⁻¹¹ 3.03 10³⁰ (1.03 10⁸) 2) / 4π²2]

r = ∛ (21.44 10³⁵ / 39.478)

r = ∛(0.0543087 10 36)

r = 0.3787 10¹² m

r = 3.787 10¹¹ m

7 0

3 years ago

If NEPA charges 5k per kWh, what is the cost of

tiny-mole [99]

Answer:

24k

Explanation:

We multiply by 200V by 24

8 0

2 years ago

Como foi a despedida do bilhete?​

Como foi a despedida do bilhete?