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MariettaO [177]
3 years ago
14

Every winter I fly home to Michigan. It takes 5.2 hours. What is my average speed

Physics
1 answer:
Nataliya [291]3 years ago
4 0
Yr average speed would be about 1151.75 really depends
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The numbers of times you do lift without resting during a muscle training workout is called
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3 years ago
A 2kg blob of putty moving at 4 m/s slams into a 6kg blob of putty at rest what is the speed of the to stick together blobs imme
andrew11 [14]
<h2>Answer</h2>

1m/s

<h2>Explanation</h2>

Given that:

<em>Mass of first blob = 2kg = m1</em>

<em>Velocity of blob = 4m/s = v1</em>

<em>Mass of second blob = 6kg = m2</em>

<em>Velocity of blob = 0m/s = v2</em>

<em />

To find:

<em>Final velocity = Vf</em>

<em />

<em>This question is of inelastic collision which is any collision between objects in which some energy is lost.</em>

<em />

<h3>Formula to be use:</h3><h2>(m1*v1) + (m2*V2) = Vf(m1 + m2)</h2>

(2*4) + (6*0) = Vf(2+6)

8 + 0 = Vf(8)

8 = Vf(8)

Vf = 1 m/s

So the speed of two blobs immediately after colliding = 1 m/s

3 0
3 years ago
A minimum price, set by the government, that must be paid for a good or service is called a _____.
nirvana33 [79]

"Minimum" means a solid barrier under you, so you can't go
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3 0
3 years ago
Read 2 more answers
A rope of negligible mass supports a block that weighs 30.0 N. as shown below. The maximum tension the rope can support without
Mars2501 [29]

Answer:

a = 6.7 m/s²

Explanation:

The formula to apply here is :

Mass * acceleration = Tension -weight

m*a = Ft -mg  -----where m is mass of block, a is acceleration , Ft  is force due to tension.

Given in the question that ;

Mass of block = 3 kg

Ft = 50 N

g= 10

m*a = Ft -mg

3*a = 50-30

3a= 20

a= 20/3

a= 6.7 m/s²

8 0
3 years ago
A tennis ball is struck in such a way that it leaves the racket with a speed of 31.0m/s in the horizontal direction. When the ba
bearhunter [10]

Answer:

Height of the racket ball = 0.86 m

Explanation:

Given:

Speed of the tennis ball,v_x= 31 m/s

Distance covered, R_x = 13.3 m

We have to find the height of the racket ball when it left the racket.

Lets say that the time taken by the ball to hit the court be 't' seconds.

⇒ time=\frac{distance}{speed}

⇒ time=\frac{R_x}{v_x}

⇒ t=\frac{13.3\ m}{31.0\ ms^-^1}

⇒ t=0.42 seconds

Now we have to find the height lets say that the height is 'h' meter.

⇒ h_y=u_yt + \frac{a_yt^2}{2}     ...<em>second equation of motion</em>

⇒ h_y=0 + \frac{gt^2}{2}          <em>...initial velocity = 0 and acceleration = gravity </em>

⇒ h_y=\frac{9.8(0.42)^2}{2}

⇒ h_y=\frac{1.72}{2}

⇒ h_y=0.86 meter.

So the height of the racket ball when it left the racket is of 0.86 m.

5 0
3 years ago
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