An expression which can be used to evaluate the relative error in g (in terms of h, Δh, t, and Δt) is: 
<h3>What is
relative error?</h3>
Relative error can be defined as a measure of the ratio of an absolute (real) value of a measurement to an expected (theoretical) value. Also, it's independent of the magnitude of its values.
<h3>How to evaluate the
relative error in
g?</h3>
In order to write this expression, we would divide the absolute (real) value by the expected (theoretical) value as follows:
<u>Note:</u> g = 2h/t²
Read more on relative error here: brainly.com/question/13370015
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To solve this problem, let us first assume that the
hydrogen gas acts like an ideal gas. So that we can make use of the ideal gas
equation:
P V = n R T
where P is the pressure, V is the volume, n is the number
of moles, R is the universal gas constant and T is the absolute temperature
Since it is given that T and P is constant therefore we
can write the equation as:
V / n = k
So equating the two conditions:
V1 / n1 = V2 / n2
We can now solve for the new V2 given n2 = 0.125:
2 L / 820 mol = V2 / 0.125 mol
V2 = 3.05 x 10^-4 L
<span>The new volume is about 3.05 x 10^-4 L which is equivalent
to 0.3 mL</span>
Answer : <em> The period increases and the frequency decreases</em>.
Explanation :
Gamma rays are the rays having frequency( 
) greater than 
and frequency of microwave lie between 300 MHz to 300 GHz.
Since, 
So, as we move from gamma rays to microwaves the energy increases because frequency is increasing.
Also, Time period 
We can say that as the time period increases, frequency decreases.
Answer:
he correct answer is V = ER
Explanation:
In this exercise they give us the electric field on the surface of the sphere and ask us about the electric potential, the two quantities are related
ΔV = ∫ E.ds
where E is the elective field and normal displacement vector.
Since E is radial in a spray the displacement vector is also radial, the dot product e reduces to the algebraic product.
ΔV = ∫ E ds
ΔV = E s
since s is in the direction of the radii its value on the surface of the spheres s = R
ΔV = E R
checking the correct answer is V = ER
