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3 years ago

Give two examples of pure substances and two examples of mixtures

Physics

2 answers:

nikdorinn [45]3 years ago

7 0

Answer:

1 kerosene is the pure substance, salt and water is the mixture substance

lions [1.4K]3 years ago

5 0

Answer:

pure substansubdiamond nd sulphur. mixture:salt nd oil ,oil nd water

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Correctly label the various structures of the membranous labyrinth of the ear.

Ronch [10]

Answer:

left side top to bottom:

- saccule

- utricle

- ampullae

- semicircular duct: anterior

- semicircular duct: lateral

- semicircular duct: posterior

right side top to bottom:

- cochlear duct

- spiral ganglion of cochlea

- cochlear nerve

- vestibular nerve

7 0

3 years ago

Usain Bolt is the fastest human at 12.4 m/s. If Usain Bolt had a mass of 94kg, what was Usain Bolt’s KE?

Fittoniya [83]

Answer:The fastest recorded human footspeed was recorded between 60 and 80m in Bolt's world record 9.58-second 100m final in Berlin in 2009. Bolt was clocked at 44.72km/h, which is 27.8mph. The Jamaican covered the distance between 60-80m in a time of just 1.61 seconds

Explanation:

pls brainlist too

3 0

3 years ago

You prepare tea with 0.250 kg of water at 85.0 ºC and let it cool down to room temperature (20.0 ºC) before drinking it. Essenti

vladimir2022 [97]

Answer:

232 J/K

Explanation:

The amount of heat gained by the air = the amount of heat lost by the tea.

q_air = -q_tea

q = -mCΔT

q = -(0.250 kg) (4184 J/kg/ºC) (20.0ºC − 85.0ºC)

q = 68,000 J

The change in entropy is:

dS = dQ/T

Since the room temperature is constant (isothermal):

ΔS = ΔQ/T

Plug in values (remember to use absolute temperature):

ΔS = (68,000 J) / (293 K)

ΔS = 232 J/K

5 0

3 years ago

A test rocket is launched vertically from ground level (y = 0 m), at time t = 0.0 s. The rocket engine provides constant upward

Romashka-Z-Leto [24]

The rocket starts at rest, so its initial velocity is 0. If the burn phase lasts $t$ seconds, then during this interval the rocket's velocity is

$v=at\implies a=\dfrac{30\,\frac{\mathrm m}{\mathrm s}}t$

and its position is

$x=\dfrac12at^2\implies a=\dfrac{2(49\,\mathrm m)}{t^2}$

So we have

$\dfrac{30\,\frac{\mathrm m}{\mathrm s}}t=\dfrac{2(49\,\mathrm m)}{t^2}\implies t=3.3\,\mathrm s$

and the answer is C.

4 0

3 years ago

Car A with a mass of 725 kilograms is traveling east at an initial velocity of 15 meters/second. It collides head–on with car B,

ikadub [295]

Answer:

$p_t_o_t_a_l=250kg\frac{m}{s}$

Explanation:

The total momentum of a system is defined by:

$(mv)_t_o_t=m_1v_1+m_2v_2+...$

Where,

$(mv)_t_o_t$ is the total momentum or it could be expressed also as $p_t_o_t_a_l$ .

$m_1$ and $m_2$ represents the masses of the objects interacting in the system.

$v_1$ and $v_2$ are the velocities of the objects of the system.

Remember: The momentum is a fundamental physical magnitude of vector type.

We have:

$m_1=725 kg$

$v_1=15\frac{m}{s}\\m_2=625 kg$

We are going to take the east side as positive, and the west side as negative. Then the velocity of the car B, has to be negative. It goes in a different direction from car A.

$v_2=-17\frac{m}{s}$

Then the total momentum of the system is:

$p_t_o_t_a_l=m_1v_1+m_2v_2\\p_t_o_t_a_l=(725kg)(15\frac{m}{s})+(625kg)(-17\frac{m}{s})\\p_t_o_t_a_l=10875kg\frac{m}{s}-10625kg\frac{m}{s}\\p_t_o_t_a_l=250kg\frac{m}{s}$

8 0

4 years ago

Give two examples of pure substances and two examples of mixtures​

Give two examples of pure substances and two examples of mixtures