Answer:(a)360N,(b)171N,(c)2.702m
Explanation:
(a)Maximum Friction Force =
=360 N
(b)Moment about Ground Point
(c)
Here maximum friction force can be 360 N
Therefore 
Where x is the maximum distance moved by man along the ladder
740x=2000
x=2.702m
<span>Answer:
sin(incidence)/sin(refraction) = n_refraction/n_incidence
sin(50) / sin(x) = 1.5 / 1
sin(50)/1.5 = sin(x)
sin(x) = 0.511
x = 30.71o
B]
50 degrees, same as the angle going in.
You can show that by reversing the steps in A.
sin(30.7)/sin(x) = 1/1.5
C]
The glass is 5 cm thick.
The reference angle = 30.7o
Tan(30.7) = displacement / thickness
Tan(30.7) = x / 5
5*sin(30.7) = x
x = 2.97 cm which is the displacement.</span>
Answer:
109.32 N/m
Explanation:
Given that
Mass of the hung object, m = 8 kg
Period of oscillation of object, T = 1.7 s
Force constant, k = ?
Recall that the period of oscillation of a Simple Harmonic Motion is given as
T = 2π √(m/k), where
T = period of oscillation
m = mass of object and
k = force constant if the spring
Since we are looking for the force constant, if we make "k" the subject of the formula, we have
k = 4π²m / T², now we go ahead to substitute our given values from the question
k = (4 * π² * 8) / 1.7²
k = 315.91 / 2.89
k = 109.32 N/m
Therefore, the force constant of the spring is 109.32 N/m
If it is a matter of which way you are going you could lean forward. It would help to put all the weight opposite of where you are falling.
The 2 means there are two phosphate ions in a molecule of magnesium phosphate.
