A = 5a
B = 2x
C = 6x^2
D = 5/7
E = 2/11
F= 6/x^2
G = 6a
H = -7x
$e\cdot e^x -e^{-2}=-2$
$\implies e^{x+1}=e^{-2}-2$
note that RHS is negative. (because e with negative exponent is less than 1)
and LHS is always positive.
so there cannot be any solution
(-2)(-5)(-7)
(10)(-7)
-70
The product is -70
Answer:
80%
Step-by-step explanation:
Let's call the past exam mark m,
m*105%=84
m*105/100=84
m=84/(105/100)
m=80
Hope this helps!
here is what I think since 2 multiplied by 15 equals 30 you at 35 more to that 30 and you get the answer 60. Is that how it is supposed to go?
