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Evgen [1.6K]
3 years ago
12

How many grams of Chromium(III) nitrate are produced when Chromium reacts with 0.85 moles of Lead(IV) nitrate to produce chromiu

m(III) nitrate and lead?
Chemistry
1 answer:
mina [271]3 years ago
7 0

Grams of Chromium(III) nitrate produced : 268.95 g

<h3>Further explanation</h3>

Given

0.85 moles of Lead(IV) nitrate

Required

grams of Chromium(III) nitrate

Solution

Reaction

Balanced equation :

<em>2Cr₂ + 3Pb(NO₃)₄ ⇒ 4Cr(NO₃)₃ + 3Pb </em>

From the equation, mol ratio of Pb(NO₃)₄  : Cr(NO₃)₃ = 3 : 4, so mol Cr(NO₃)₃

mol Cr(NO₃)₃ =

\tt \dfrac{4}{3}\times 0.85=1.13

Mass of Chromium(III) nitrate (MW=238.0108 g/mol) :

mass = mol x MW

mass = 1.13 x 238.0108

mass = 268.95 g

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