Answer:
The cell potential is 0.0296V
Explanation:
Please see the attachment below
Answer:
The correct answer is 6.265 M.
Explanation:
To find the molarity of the solution, we first must recall that molarity represents the number of moles of solute divided by the number of liters of solution. Thus, our first step should be to convert the solute amount in grams to moles, using the given molar mass.
266.07 g * (1 mol/169.88 g) = 1.5662 mol
Now, we can find the molarity using the following formula:
Molarity = moles solute/liters solution
M = 1.5662 mol/0.25 L
M = 6.265 M
Therefore, the molarity of the solution is 6.265 M.
Hope this helps!
Answer:
%Ga by mass in sample of 
is 23.0%
Explanation:
Molar mass of AgBr = 187.77 g/mol
So, 0.299 g of AgBr = 
moles of AgBr = moles of Br = 0.00159 moles of Br
Br in AgBr comes from
So, there are 0.00159 moles of Br in 0.165 g of
Molar mass of Br = 79.904 g/mol
So, mass of Br in 0.165 g of = 
= 0.127 g
So, mass of Ga in sample of = (0.165-0.127) g = 0.038 g
So, %Ga by mass in sample of = [(mass of Ga)/(mass of )]
%
= 
%
= 23.0%
Answer:
GAUUUUUUUUUUUUUUUUUUUUUUUuR
Explanation:
