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VladimirAG [237]
3 years ago
8

WILL MARK THE BRAINLEST

Chemistry
2 answers:
WITCHER [35]3 years ago
5 0
C I think but if I’m wrong I’m really sorry
alexdok [17]3 years ago
3 0

Answer:

a. Hh, hh

b. hh

c. 50%

d. 50%

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What is the product of the reduction of an aldehyde?
Elza [17]

Answer:

Achol

Explanation:

Reduction of other aldehydes gives primary alcohols. Reduction of ketones gives secondary alcohols. The acidic work-up converts an intermediate metal alkoxide salt into the desired alcohol via a simple acid base reaction.

5 0
3 years ago
Consider the following reaction:
mario62 [17]

Answer: 15.7 liters

Explanation: reaction is 2H2 + O2. -> 2H2O

Because all substance still are gases, volumes in

STP conditions are proportional to amount of moles.

Amount of water is same as Hydrogen. Also volume is same.

7 0
3 years ago
Calculate the volume in liters of 14.4 moles of neon gas at STP
AlekseyPX

Answer:

its 8 uniys of neon gas i am taking chenistry

4 0
3 years ago
A solution containing 60 grams of nano3 completely dissolved in 50. Grams of water at 50°c is classified as being
Igoryamba

Answer:

<em>A solution containing 60 grams of nano3 completely dissolved in 50. Grams of water at 50°c is classified as being</em> <u>supersaturaded</u>

Explanation:

This question is about solubility.

Regarding solubility, the solutions may be classified as:

  • Unsaturated: the concentration is below the maximum concentration permited at the given temperature.

  • Saturated: the concentration is the maximum permitted at the given temperature, under normal conditions.

  • Supersaturated: the concentration has overcome the maximum permitted at the given temperature. This is possible only under special conditions and is a very unstable state.

Each substance has its own, unique solubility properties. So, in order to tell the state of the solution you need to compare with either solubility tables, or solubility curves; or run you own experiments.

  • In internet you can find the solubility curve of NaNO₃ showing the solubility for a wide range of temperatures.

  • In such curve the solubility of NaNO₃ at 50°C is about 115 g of NaNO₃ per 100 g  of water.

  • Hence, do the proportion to determine the amount of solute that can be dissolved in 50 grams of water at 50°CÑ

       115 g NaNO₃ / 100 g H₂O = x / 50 g H₂O  ⇒ x =  57.5 g NaNO₃

  • <u>Conclusion</u>: 50 grams of water can contain 57.5 g of NaNO₃ dissolved; so, <em>a solution containing 60 g of NaNO₃ completely dissolved in 50 grams of water is supersaturated.</em>

<em />

3 0
3 years ago
How do you do this ???
trapecia [35]
1. 254 cal = 1,062.736 joules
2. 126 cal = 527.184 joules 
3. 98 cal = 410.032 joules
4. 704 cal = 2,945.536 joules
5. 682 cal = 2,853.488 joules
5 0
3 years ago
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