Calculate the cell potential, Ecell, of a concentration cell containing a 0.1 M solution of Zn2 and a 1.0 M solution of Zn2

1 answer:

3 0

Answer:

The cell potential is 0.0296V

Explanation:

Please see the attachment below

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andrew11 [14]

Question

Given the electron configuration of an atom: 1s2, 2s2, 2p5 , what is the element?

Answer:

A.) Fluorine

Hope this helps!

4 0

3 years ago

Luda [366]

Answer:

10g/cm^3, I think.

Explanation:

2x2x2=8cm^3 for the volume.

Divide 80g by that, you get 10g/cm^3, I think.

3 0

3 years ago

worty [1.4K]

Answer:

The specific heat of the sample unknown metal is approximately 0.45 J/g °C.

General Formulas and Concepts:
Thermodynamics

Specific Heat Formula: $\displaystyle q = mc \triangle T$

Explanation:

Step 1: Define

Identify variables.

m = 112 g

ΔT = 20.0 °C

q = 1004 J

Step 2: Solve for c

Substitute in variables [Specific Heat Formula]: $\displaystyle 1004 \ \text{J} = (112 \ \text{g})(c)(20.0 \ ^{\circ} \text{C})$
Simplify: $\displaystyle 1004 \ \text{J} = (2240 \ \text{g} \ ^\circ \text{C})c$
Isolate c: $\displaystyle c = 0.448214 \ \text{J} / \text{g} \ ^\circ \text{C}$
Round [Sig Figs]: $\displaystyle c \approx 0.45 \ \text{J} / \text{g} \ ^\circ \text{C}$