The answer is -1, because protons are positive charges and electrons are negative charges. If you subtract them you would get you answer if -1
Answer:
When a light wave goes through a slit, it is diffracted, which means the slit opening acts as a new source of waves. How much a light wave diffracts<em> (how much it fans out)</em> depends on the wavelength of the incident light. The wavelength must be larger than the width of the slit for the maximum diffraction. Thus, for a given slit, red light, because it has a longer wavelength, diffracts more than the blue light.
The corresponding relation for diffraction is
,
where is the wavelength of light, is the slit width, and is the diffraction angle.
From this relation we clearly see that the diffraction angle is directly proportional to the wavelength of light—longer the wavelength larger the diffraction angle.
Answer:
The total distance traveled is 736 m
Solution:
According to the question:
Initial velocity, v = 0
(since, the car is starting from rest)
Time taken, t = 8 s
Now, the distance covered by it in 8 s is given by the second eqn of motion:
Now, to calculate the velocity, we use eqn 1 of motion:
v' = v + at
v' = 0 + 4(8) = 32 m/s
Now, the distance traveled by the car with uniform velocity of 32 m/s for t' = 19 s:
distance, d' = v't'
Total distance traveled = d + d' = 128 + 608 = 736 m
Answer:
due to the effect of gravity begins thermonuclear fusion processes, in these processes energy is released in the form of electromagnetic radiation
Explanation:
The Sun is a star of great size, which due to the effect of gravity begins thermonuclear fusion processes, in these processes energy is released in the form of electromagnetic radiation.
This radiation crosses the different layers of the Sun and escapes from it in the form of light that is emitted throughout the radiation spectrum, due to the temperature reached by the Sun about 5500K the most likely radiation is around 5500 nm corresponding to the green- yellow of the visible spectrum, but the entire spectrum is emitted with different intensity according to Stefan's law
In quantum mechanics this spectrum can also be analyzed as the emission of particles called photons, where each one is characterized by an energy and has a moment equal to zero, the energy of these photons is related to their frequency by the Planck equation
E = h f