Remmber you can't divide by 0
if you can canel out something from both that is a hole
exampe if you had y=[(x-2)(x+3)]/(x-2), then the equation is y=x+3 with a hole at x=2 (since x=2 to make x-2=0 true)
so
y=2x-3 is theh graph
zero at y=0 or x=3/2
(1.5,0) is the zero
set factored out thing to zero
x+4=0
x=-4
at x=-4
input into later one
y=2x-3
y=2(-4)-3
y=-8-3
y=-11
hole at (-4,-11)
the hole is at (-4,-11)
zero at (3/2,0)
Answer:
see explaination
Step-by-step explanation:
the diagram shows two equal parts being the divided by two in the equations. The parts are worth 8 meaning if you divide 16 by 8 it is 2 because there are two parts.
Answer:
no solutions
Step-by-step explanation:
-3x + 7 = 5x + 4 - 8x
Combine like terms
-3x+7 = -3x+4
Add 3x to each side
-3x+7+3x = -3x+4+3x
7 = 4
This is not a true statement so there are no solutions
Answer is C...
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hope this helped
I think it’s 84 you multiply 14 and 12 then divide by 2 since it is a triangular prism