Answer:
Atomic size gradually decreases from left to right across a period of elements.
Explanation:
1. Melting point is the temperature at which the solid turns to liquid. In order to reach this point, the intermolecular forces of the solid must be broken so that it would incorporate the molecular arrangement of a liquid.<em> So, the stronger the intermolecular forces, the greater the energy which consequently leads to higher melting points.</em>
2. Vapor pressure is the pressure exerted by the gas above its solid or liquid substance. It is closely related to volatility, which is the ability of the substance to convert from liquid to gas at a certain temperature. <em>The stronger the intermolecular force, the less volatile the substance is which is manifested in increasing vapor pressure.</em>
3. Boiling point has the same concept as melting point, but the change is from liquid to gas. <em>So, the stronger the intermolecular forces, the greater the energy which consequently leads to higher boiling points.</em>
4. Viscosity is the ease of fluidity. Solids, which have stronger intermolecular forces are not viscous at all. <em>So, the stronger the intermolecular forces, the viscosity decreases.</em>
5. Surface tension is the force the substance exerts near its surface or interface. <em>The stronger the intermolecular force, the stronger the surface tension. </em>
C) The atom must contain some centrally located positive charge. He called this core of positive charge the nucleus.
Explanation:
Rutherford concluded from his experiment that the atom contains some centrally located positive charge. He called the core the nucleus.
Rutherford developed the nuclear model of the atom.
- In a bid to explain his observation, Rutherford suggested the nuclear model.
- The model consists of small positively charged center called the nucleus.
- Nearly all the mass is concentrated in the nucleus.
- The extranuclear space is made up of electrons orbiting the nucleus.
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If the reacted oxygen is 35.1 g.
H2O mass= (35.1+9.8)-29.6
= 19.3g
The balanced equation for the reaction is as follows;
2H₂S + SO₂ —> 2H₂O + 3S
Stoichiometry of H₂S to SO₂ is 2:1
Limiting reactant is fully used up in the reaction and amount of product formed depends on amount of limiting reactant present.
Number of H₂S moles - 8.0 g / 34 g/mol = 0.24 mol of H₂S
Number of SO₂ moles = 12.0 g / 64 g/mol = 0.188 mol of SO₂
According to molar ratio of 2:1
If we assume H₂S to be the limiting reactant
2 mol of H₂S reacts with 1 mol of SO₂
Therefore 0.24 mol of H₂S requires - 1/2 x 0.24 = 0.12 mol of SO₂
But 0.188 mol of SO₂ is present therefore SO₂ is in excess and H₂S is the limiting reactant.
H₂S is the limiting reactant
Amount of S produced depends on amount of H₂S present
Stoichiometry of H₂S to S is 2:3
2 mol of H₂S forms 3 mol of S
Therefore 0.24 mol of H₂S forms - 3/2 x 0.24 mol = 0.36 mol of S
Mass of S produced = 0.36 mol x 32 g/mol = 11.5 g of S is produced
