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statuscvo [17]
3 years ago
9

Question 10 I need help

Chemistry
1 answer:
VashaNatasha [74]3 years ago
6 0
Sorry I can’t see it very well
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The attractions that allow molecules of krypton to exist in the solid phase are due to:
OLga [1]

Answer:

4) Van der waals forces

Explanation:

Krypton (Kr) belongs to the noble gas group and has fully filled valence orbitals. In the solid phase, Kr exists as a white solid with a face centered cubic structure.

Intermolecular forces of attraction from the strongest to the weakest include:

Ionic > hydrogen bonding > dipole-dipole > london dispersion

Kr is monoatomic and non-polar. When fully filled (stable) valence orbitals of 2 Kr atoms approach each other in close proximity they experience a repulsive force which prevents the formation of strong bonds. Thus, the only force of attraction in Kr is the long range weak Van Der Waals force also known as the london dispersion force.

7 0
3 years ago
one ball rolls along a shelf at a steady rate. a second ball rolls off the shelf and gains speed as it falls in a curved path. w
Salsk061 [2.6K]
The ball that rolls at a steady rate
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3 years ago
What can be concluded about the atom from knowing that oxygen 18 has an atomic number of 8?
Vinvika [58]
<span>The atomic number of a neutral atom is equal to the number of protons and the number of electrons of the atom. The atomic weight meanwhile is equal to the sum of the number of protons and number of neutrons.Hence we can say that the number of protons is 8 and the number of neutrons is 10. </span>
7 0
3 years ago
Read 2 more answers
Why is the hydrogen molecule stable with only 2 electrons while the fluorine molecule needs to have 8 electrons available for ea
Whitepunk [10]

Answer:

By sharing their valence electrons, both hydrogen atoms now have two electrons in their respective valence shells. Because each valence shell is now filled, this arrangement is more stable than when the two atoms are separate.

Explanation:

4 0
2 years ago
The adult blue whale has a lung capacity 5.0\times10^3 5.0 Ã 10 3 l. calculate the mass of air (assume an average molar mass of
Andre45 [30]
For this item, we need to assume that air behaves like that of an ideal gas. Ideal gases follow the ideal gas law which can be written as follow,
    PV = nRT
where P is the pressure, 
V is the volume,
 n is the number of mols,
R is the universal gas constant, and 
T is temperature

In this item, we are to determine first the number of moles, n. We derive the equation,
       n = PV /RT
Substitute the given values,

    n = (1 atm)(5 x 10³ L) / (0.0821 L.atm/mol.K)(0 + 273.15)
    n = 223.08 mols

From the given molar mass, we calculate for the mass of air.
   m = (223.08 mols)(28.98 g/mol) = 6464.9 g

<em>ANSWER: 6464.9 g</em>
8 0
3 years ago
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