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Maksim231197 [3]
3 years ago
14

What is the Na+ concentration in each of the following solutions:

Chemistry
1 answer:
iren [92.7K]3 years ago
5 0

Sodium Sulfate = Na2(SO4) meaning there are two ions of Na+ in one mole of Sodium Sulfate the M stands for Molarity, defined as Molarity = (moles of solute)/(Liters of solution), So if the Na2SO4 solution is 3.65M that means one Liter of has 3.65 moles of Na2SO4, the stoichiometry of Na2SO4 shows that there would be two Na+ ions in solution for every one Na2SO4.

Therefore if 3.65 moles of Na2SO4 was to dissolve, it would produce 7.3 moles of Na+, and since this is still a theoretical solution, we can assume 1 L of solution.

Finally we find [Na+] = 2*3.65 = 7.3M

Use the same logic for parts b and c




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Chapter 15 of your textbook discusses conjugation and various reactions of 1,3-dienes. In CHE 321, we discussed various ways to
xxMikexx [17]

Answer:

Dienes are alkenes that contain two carbon-carbon double bonds, so they have the same properties as these hydrocarbons.

In the attached file are the two reactions of dienes production.

Explanation:

Two ways to obtain dienes are as follows:

-Reaction of oxidative dehydrogenation of an alkane, is an exothermic process and occurs at lower temperatures, diene and water are formed, generating greater conversion at lower temperature levels.

-Dehydration of primary alcohols. The treatment of alcohols with acid at elevated temperatures produces dienes due to water loss. For example, heating ethanol in the presence of sulfuric acid produces ethene by the loss of a water molecule.

Download pdf
5 0
3 years ago
An excited ozone molecule, O3*, in the atmosphere can undergo one of the following reactions,O3* → O3 (1) fluorescenceO3* → O +
Maurinko [17]

Answer:

The simplified expression for the fraction  is  \text {X} =    \dfrac{  {k_3  \times cM} }{k_1 +k_2 + k_3 }

Explanation:

From the given information:

O3* → O3                   (1)    fluorescence

O + O2                      (2)    decomposition

O3* + M → O3 + M    (3)     deactivation

The rate of fluorescence = rate of constant (k₁) × Concentration of reactant (cO)

The rate of decomposition is = k₂ × cO

The rate of deactivation = k₃ × cO × cM

where cM is the concentration of the inert molecule

The fraction (X) of ozone molecules undergoing deactivation in terms of the rate constants can be expressed by using the formula:

\text {X} =    \dfrac{ \text {rate of deactivation} }{ \text {(rate of fluorescence) +(rate of decomposition) + (rate of deactivation) }  } }

\text {X} =    \dfrac{  {k_3 \times cO \times cM} }{  {(k_1 \times cO) +(k_2 \times cO) + (k_3 \times cO \times cM) }  }

\text {X} =    \dfrac{  {k_3 \times cO \times cM} }{cO (k_1 +k_2 + k_3  \times cM) }

\text {X} =    \dfrac{  {k_3  \times cM} }{k_1 +k_2 + k_3  }    since  cM is the concentration of the inert molecule

7 0
4 years ago
Which is the heaviest element produced in large stars by nuclear fusion near the end of their life cycle?
Rama09 [41]

Iron is the heaviest element produced in large stars by nuclear fusion near the end of their life cycle .

<h3>What do you mean by the nuclear fusion ?</h3>

Nuclear fusion is the process by which two light atomic nuclei combine to form a single heavier one while releasing massive amounts of energy.

The main advantage of nuclear fusion is it is safe source for the generation of electricity.

Characteristics of nuclear fusion -:

  • The main characteristic of nuclear fusion is that it involves formation of a singular particle from two or more atoms.

  • Unlike nuclear fission, nuclear fusion is common in nature- just hard to recreate.

  • Nuclear fusion typically produces few radioactive particles .

  • Fusion works by applying a great deal of pressure to overcome .

Hence ,Iron is the heaviest element produced in large stars by nuclear fusion near the end of their life cycle .

Learn more about nuclear fusion ,here:

brainly.com/question/12701636

#SPJ2

6 0
1 year ago
Read 2 more answers
12 = 3X X = <br> 7X = 57 X = <br> 11X = 27.7 X =
dybincka [34]

Answer:
1. x=4
2.x=\frac{57}{7}
3.x=\frac{27.7}{11}

Explanation:

Given the following questions:

12=3x
7x=57
11x=27.7

In order to find the answers to these questions, we have to recognize that in order to isolate the variable we need to divide on both sides.

Question one:
12=3x
\frac{3x}{3} =\div3
12\div3=4
x=4

Question two:
7x=57
\frac{7x}{7} =\div7
57\div7=8.14285714=\frac{57}{7}
x=\frac{57}{7}

Question three:
11x=27.7
\frac{11x}{11} \div11
27.7\div11=2.51818182=\frac{27.7}{11}
x=\frac{27.7}{11}

Hope this helps.

3 0
2 years ago
Decide whether or not each of the following metals dissolves in 1 M HCl. For these metals that do dissolve, enter a balanced red
Pachacha [2.7K]
I believe copper would dissolve iron would just get the rust off of it. Copper would boil then dissolve. idk what the second part would be. Hope this helps!
5 0
4 years ago
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