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3 years ago

HELP HURRY !! is the graph a function ?

Mathematics

1 answer:

quester [9]3 years ago

4 0

Answer:

Yes.

Step-by-step explanation:

If you use the vertical line test, you'll see that the line only touches the graph at one point.

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Given the figure, find the values of x and z.

matrenka [14]

Answer:

$z = 62 \\ 6x + 52 = 180 - 62 \\ 6x = 66 \\ x = 11$

7 0

3 years ago

Read 2 more answers

Solve 73 make sure to also define the limits in the parts a and b

Aleks04 [339]

73.

$f(x)=\frac{3x^4+3x^3-36x^2}{x^4-25x^2+144}$

$\lim_{x\to\infty}f(x)=\lim_{x\to\infty}(\frac{3+\frac{3}{x}-\frac{36}{x^2}}{1-\frac{25}{x^2}+\frac{144}{x^4}})=3$ $\lim_{x\to-\infty}f(x)=\lim_{x\to-\infty}(\frac{3+\frac{3}{x}-\frac{36}{x^2}}{1-\frac{25}{x^2}+\frac{144}{x^4}})=3\cdot\frac{1}{2}=3$

Since we can't divide by zero, we need to find when:

$x^4-2x^2+144=0$

But before, we can factor the numerator and the denominator:

$\begin{gathered} \frac{3x^2(x^2+x-12)}{x^4-25x^2+144}=\frac{3x^2((x+4)(x-3))}{(x-3)(x-3)(x+4)(x+4)} \\ so: \\ \frac{3x^2}{(x+3)(x-4)} \end{gathered}$

Now, we can conclude that the vertical asymptotes are located at:

$\begin{gathered} (x+3)(x-4)=0 \\ so: \\ x=-3 \\ x=4 \end{gathered}$

so, for x = -3:

$\lim_{x\to-3^-}f(x)=\lim_{x\to-3^-}-\frac{162}{x^4-25x^2+144}=-162(-\infty)=\infty$ $\lim_{x\to-3^+}f(x)=\lim_{x\to-3^+}-\frac{162}{x^4-25x^2+144}=-162(\infty)=-\infty$

For x = 4:

$\lim_{x\to4^-}f(x)=\lim_{n\to4^-}\frac{384}{x^4-25x^2+144}=384(-\infty)=-\infty$ $\lim_{x\to4^-}f(x)=\lim_{n\to4^-}\frac{384}{x^4-25x^2+144}=384(-\infty)=-\infty$

4 0

1 year ago

Find the range of possible values for the following measurements, which were rounded to the nearest mm, tenth of m, and hundredt

zmey [24]

The required range of the data is 24mm

The range of data is the difference between the largest value and the least value in a set of data.

Since we are not given the range of data. Let's assume we gave the following data:

34mm, 30mm, 20mm, 44mm, 31mm

From the data

Highest measurement = 44mm

Least measurement = 20mm

Find the range

Range = Highest measurement - Least measurement

Range = 44mm - 20mm

Range = 24mm

Hence the required range of data is 24mm

<em>NB: The concept can be applied to any set of data given for other measurements in (b) and (c)</em>

<em>Learn more here: brainly.com/question/1786006</em>

6 0

3 years ago

A ball is thrown up into the air from a building modeled by the equation:

Arlecino [84]

Answer:

After two seconds

h(2) = -16(2^2) + 115(2) + 19

h(2) = -64 + 115(2) +19

h(2) = 185

Let me know if this helps!

3 0

3 years ago

PLS HELP ME

s2008m [1.1K]

The students on the right hand side had better overall results

There were less people on the left hand side of the room this affects the average even with the right hand side having two zeros, another thing which the left hand side didn’t have.

Hope I helped

3 0

2 years ago