When pressure in a chemical reaction increases, the equilibrium will shift towards the side of the reaction with fewer moles of gas. When there is a decrease in pressure, the equilibrium will shift towards the side of the reaction with more moles of gas.Therefore; in this case; increased the Equilibrium will shift to the left and favor the reverse reaction. This is because the side of products has more moles compared to the side of reactants, thus increased in pressure will aid conversion of products to reactants.
I am pretty sure the answer is . But I might be wrong.
Answer:
The correct answers are given below
Explanation:
1 An increase of one in atomic number and no change in the mass number.
2 All the above statements are correct.
3 A decrease of one in atomic number and a decrease of four in mass number.
4 Have a high neutron to proton ratio.
Atomic radius is the distance from the nucleus to the last valance electron up to which the effect nucleus can be felt. The size of the atom depends on the Electrostatic interaction between nucleus and electron. Number of atomic orbitals present. With the increase in numbers of orbitals down the group the size of the atom increases. Again, as the numbers of electrons increases in the period ,the electrostatic interaction between nucleus and electron increases along the period. Therefore, size of atoms decreases along the period.
As expected the element with highest atomic radius is the last element of group 1 , Which is FRANCIUM ( Fr)
