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Naily [24]
3 years ago
11

Plants and animals add carbon dioxide to the atomsphere when they ____ glucose.

Chemistry
1 answer:
labwork [276]3 years ago
7 0
A! Oxidize. Hope this helps!
You might be interested in
Question is in picture below
liq [111]

The dissociation of cadmium chloride is as follows: CdCl₂(s) → Cd⁺²(aq) + 2Cl⁻(aq)

<h3>What is dissociation?</h3>

Dissociation is the process by which a compound body breaks up into simpler constituents; said particularly of the action of heat on gaseous or volatile substances.

It is a chemical reaction in which a compound breaks apart into two or more components. The general formula for a dissociation reaction follows the form:

AB → A + B

According to this question, cadmium chloride undergoes dissociation into cadmium and chlorine ions as follows:

CdCl₂(s) → Cd⁺²(aq) + 2Cl⁻(aq)

Learn more about dissociation at: brainly.com/question/28952043

#SPJ1

8 0
1 year ago
How can a Hydrogen atom turn into a<br> Hydrogen ion (H+)?
Butoxors [25]

Answer:

By losing an electron

Explanation:

Electrons have a negative charge. So, losing one would give an element a more positive charge. You can usually find a hydrogen ion (H+) in substances like acids.

3 0
3 years ago
What is the total pressure in a container with 256 mm Hg of Oz, 198 mm Hg of He,
irina1246 [14]

Answer:

P(total pressure) = 504 mmHg = 504mm/760mm/atm = 0.663 atm

Explanation:

Apply Dalton's Law of Partial Pressures.

P(total) = ∑Partial Pressures = ∑(256mm + 198mm + 48mm) = 504 mmHg

P(total pressure) = 504 mmHg = 504mm/760mm/atm = 0.663 atm

7 0
2 years ago
The boiling point of chloroform is 61.7 C. The enthalapy of vaporization is 31.4 kj/mol. Caculate the entropy of vaporization. D
dedylja [7]

Answer:

Δ S = 93.8 J/mol-K

Explanation:

Given,

Boiling point of chloroform = 61.7 °C

                                             = 273 + 61.7 = 334.7 K.

Enthalapy of vapourization = 31.4 kJ/mol.

Using Gibbs free   energy equation

Δ G = Δ H - T (ΔS)

at equilibrium (when the liquid is boiling), Δ G = 0

so,  0 = ΔH - T (Δ S)

      T (Δ S) = Δ H

and ΔS = ΔH / T

Δ S = (31400 J/mol.) / 334.7 K

Δ S = 93.8 J/mol-K

6 0
3 years ago
Watch the animation and identify the correct conditions for forming a hydrogen bond. check all that apply. check all that apply.
OLga [1]
The ch4 molecule exhibits hydrogen bonding.
This statement is false. A CH4 molecule do not have a hydrogen bonding instead it has dipole dipole attraction.

Hydrogen bonding occurs when a hydrogen atom is covalently bonded to an N, O, or F atom.
This would be a true statement. A hydrogen bond is present when an atom of hydrogen shares electrons with O, N or F atom.

A hydrogen bond is equivalent to a covalent bond.
This is a false statement. A hydrogen bond is an intermolecular force of attraction while covalent bond is a intramolecular force. So, they would mean different things.

a hydrogen bond is possible with only certain hydrogen-containing compounds.
This would be true. Without the presence of an hydrogen atom definitely there would be no hydrogen bond.

a hydrogen atom acquires a partial positive charge when it is covalently bonded to an f atom.
This would be true since a HF is a polar molecule.
6 0
3 years ago
Read 2 more answers
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