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Alona [7]
2 years ago
6

What is the area pleas

Mathematics
2 answers:
kiruha [24]2 years ago
6 0

Answer:

9 ft

Step-by-step explanation:

Fittoniya [83]2 years ago
3 0

The answer is 146 square feet. Hope this helps! :-)

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What is the value of cos a?
VARVARA [1.3K]

Answer:

\frac{7}{25}

Step-by-step explanation:

Using SOHCAHTOA, you know that Cosine is represented with the side adjacent to the angle (7) on top of the fraction and the hypotenuse (25) on the bottom.

4 0
2 years ago
Exponential Function:
antoniya [11.8K]

Answer:

See below

Step-by-step explanation:

<h3>Given</h3>
  • Initial population at 8:00 AM
  • 3000000
  • Growth rate = 10% = 1.1 times per 20 min
<h3>Solution</h3>

<u>1. Table</u>

<em>Note. I am not sure what are the last 3 rows. Just added next 3 terms.</em>

  • 8:00  ≡  G(0)   ≡   3000000              ≡  3000000
  • 8:20  ≡  G(1)    ≡   3000000 *1.1        ≡  3300000
  • 8:40  ≡  G(2)   ≡   3000000 *1.1^2    ≡  3630000
  • 9:00  ≡  G(3)   ≡   3000000 *1.1^3    ≡  3993000
  • 9:20  ≡  G(4)   ≡   3000000 *1.1^4    ≡  4392300

<u>2. Population at 10:00</u>

  • Time passed since 8:00 is 2 hours = 2*3*20 min = 6* 20 min
  • Population = 3000000*1.1^6 = 5314683

<u>3. Function to reflect the population growth</u>

  • G(x) = 3000000*1.1^x
  • G(x) - is dependent variable, population of bacteria
  • x - is independent variable, time increment of 20 min

<u>4. Population after 5 hours</u>

  • 5 hours = 5*3*20 min = 15*20 min
  • G(15) = 3000000*1.1^15 ≈ 12531745

3 0
3 years ago
Read 2 more answers
Find the derivative
zalisa [80]

First use the chain rule; take y=\dfrac{x+5}{x^2+3}. Then

\dfrac{\mathrm df}{\mathrm dx}=\dfrac{\mathrm df}{\mathrm dy}\cdot\dfrac{\mathrm dy}{\mathrm dx}

By the power rule,

f(x)=y^2\implies\dfrac{\mathrm df}{\mathrm dy}=2y=\dfrac{2(x+5)}{x^2+3}

By the quotient rule,

y=\dfrac{x+5}{x^2+3}\implies\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{(x^2+3)\frac{\mathrm d(x+5)}{\mathrm dx}-(x+5)\frac{\mathrm d(x^2+3)}{\mathrm dx}}{(x^2+3)^2}

\implies\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{(x^2+3)-(x+5)(2x)}{(x^2+3)^2}

\implies\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{3-10x-x^2}{(x^2+3)^2}

So

\dfrac{\mathrm df}{\mathrm dx}=\dfrac{2(x+5)}{x^2+3}\cdot\dfrac{3-10x-x^2}{(x^2+3)^2}

\implies\dfrac{\mathrm df}{\mathrm dx}=\dfrac{2(x+5)(3-10x-x^2)}{(x^2+3)^3}

6 0
3 years ago
Find a formula for a function that has vertical asymptotes x = 2 and x = 7 and horizontal asymptote y = 2.
Pie
Hello : 

 

hello : <span>
1 ) if : x</span>ـــــــ> ± ∞  <span>
 limf(x)   = b     ....(b</span>∈R)     so : y=b is the equation of the line horizontal asymptote.

<span>
2) if : x</span>ـــــــ> a ...(a∈R)<span>
 limf(x)   = ± ∞  
<span>so : x=a is the equation of the line vertical asymptote.</span></span>

<span><span>hint : in this exercice : a = 2 or a = 7  but : b=2</span></span>

6 0
3 years ago
X + y2 = 25 x + 3y = 33
Advocard [28]
Are these 2 different questions or is this one equation
7 0
3 years ago
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