Answer:
C the mass of the reactant molecules is the same as the mass of the product
We know, change in temperature is given by :
Putting all given values, we get :
Hence, this is the required solution.
Answer:
Mass of seawater = 512.5 gram
Explanation:
Given:
Volume of seawater = 500 ml
Density of seawater = 1.025 g/ml
Find:
Mass of seawater
Computation:
Mass of seawater = Volume of seawater × Density of seawater
Mass of seawater = 500 × 1.025
Mass of seawater = 512.5 gram
This can be solved using Dalton's Law of Partial pressures. This law states that the total pressure exerted by a gas mixture is equal to the sum of the partial pressure of each gas in the mixture as if it exist alone in a container. In order to solve, we need the partial pressures of the gases given. Calculations are as follows:
P = P1 + P2 + P3
P = (82.0575 atm.cm^3/mol.K)( 298.15 K)/1.50 x 10^3 cm^3) x (<span>0.158 mole + 0.09 mol + 0.044 mol) = 4.76 atm</span>
Answer: it would be 23820 liters i dont know thats my best answer, hope it helps!
Explanation:
you have to multiply it or divide it.
Hope it helps!! :)
