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3 years ago

Determine if the following two structures are

Chemistry

1 answer:

erastovalidia [21]3 years ago

7 0

Answer:

Identical

Explanation:

Both compounds are identical. If you rotate the compound on the left 60 degree anticlockwise you will get the compound on the right.

These are not isomers of each other because they have same structural and molecular formulas.

Also, they are related to each other because they are the same

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Which cellular organelle is responsible for digestion and for the breakdown of damaged organelles inside an animal cell but not

Arturiano [62]

It would be a Lysosome

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3 years ago

Read 2 more answers

One mole of an ideal gas<br><br> occupies a volume of 22.4<br><br> liters at

-Dominant- [34]

Answer : One mole of an ideal gas occupies a volume of 22.4 liters at STP.

Explanation :

As we know that 1 mole of substance occupies 22.4 liter volume of gas at STP conditions.

STP stands for standard temperature and pressure condition.

At STP, pressure is 1 atm and temperature is 273 K.

By using STP conditions, we get the volume of 22.47 liter.

Hnece, the one mole of an ideal gas occupies a volume of 22.4 liters at STP.

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4 years ago

Consider the conversion of 2-naphthol and 1-bromobutane into an ether via the williamson ether synthesis. list the procedural st

Lemur [1.5K]

Answer:

Following are the solution to this question:

Explanation:

Please find the complete question in the attachment.

Start of Laboratory

Dissolve 2-naphthol in the round bottom flask with ethanol.

Add pellets of sodium hydroxide and hot chips. Attach a condenser.

Heat for 20 minutes under reflux, until the put a burden dissolves.

After an additional hour, add 1-Bromobutane and reflux.

Pour the contents into a beaker with ice from a round bottom flask.

On a Bachner funnel, absorb the supernatant by vacuum filtration.

Utilizing cold water to rinse the material and dry that on the filter.

Ending of the Lab

6 0

3 years ago

A client who weighs 70 kg is receiving a solution of 0.9% sodium chloride (normal saline) 500 ml with dopamine 800 mg at 5 ml/ho

nordsb [41]

The mcg/kg/minute the client is receiving is 1.904 mcg/kg/min whose weight is 70 kg.

1 milligram (mg) = 1000 micrograms (mcg) or 0.001 grams (g) 1 g = 1000 mg 1 kilogram (kg) = 1000 g 1 kg = 2.2 pound (lb) 1 liter (L) = 1000 milliliters (mL)

The number of mcg/kg/minute = flow rate × concentration ÷ mass of client

Flow rate = 12 ml/hour = 12 ml/hour × 1 hr/60 min = 0.2 ml/min

Concentration = mass of dopamine/volume

where

mass of dopamine = 800 mg and

volume = 500 ml

Concentration =800 mg/500 ml

= 1.6 mg/ml

= 1.6 mg/ml × 1000 mcg/mg

= 1600 mcg/ml

mass of client = 70 kg

Calculating mcg/kg/minute

So, substituting the variables into the equation, we have

mcg/kg/minute = flow rate × concentration ÷ mass of client

mcg/kg/minute = 0.08 ml/min × 1600 mcg/ml ÷ 70 kg

mcg/kg/minute = 320 mcg/min ÷ 70 kg

mcg/kg/minute = 1.904 mcg/kg/min

Thus, the mcg/kg/minute the client is receiving is 1.904 mcg/kg/min

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7 0

2 years ago

What is the mass of 3.04×10^-4 mol of baking soda, NaHCO3?

Zigmanuir [339]

Answer:

0.025536g

Explanation:

no. of mole = mass/Mr

mass = Mr × no. of mole

= [23 + 1 + 12 + 3(16)] × 3.04×10^-4

= 0.025536g

= 0.0255g (3 significant figures)

8 0

3 years ago