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kvv77 [185]
3 years ago
6

Prove that (secΘ + cotΘcscΘ) / cosΘ = csc^2Θ sec^2Θ.

Mathematics
1 answer:
BabaBlast [244]3 years ago
8 0

Answer:

it is . what it is lol

Step-by-step explanation:

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Spaceship Earth, a spherical attraction at Walt Disney World’s Epcot Center, has a diameter of 50 meters. Find the surface area
Black_prince [1.1K]

The surface area of Spaceship Earth is: 7850 m^2

Step-by-step explanation:

Given

Diameter of spherical structure = d = 50 meters

As the attraction is in the form of a sphere, its radius will be used to find the surface area.

Radius = r = \frac{d}{2} = \frac{50}{2} = 25\ m

The formula for surface area of sphere is:

SA = 4\pi  r^2\\= 4 * 3.14 * (25)^2\\= 4*3.14*625\\=7850\ m^2

The surface area of Spaceship Earth is: 7850 m^2

Keywords: surface area, sphere

Learn more about surface area about:

  • brainly.com/question/1859222
  • brainly.com/question/1993757

#LearnwithBrainly

6 0
3 years ago
If a number is divided by a negative number will the outcome be positive?
Zielflug [23.3K]
That would depend...

-4 / -2 = 2........4 / 2 = 2 <== if the signs are the same
but
4 / -2 = -2.......-4 / 2 = -2 <== if the signs are different

 So basically, if the signs are the same, the result is positive and if the signs are different, the result is negative
7 0
3 years ago
Helppp meeee plsssss
serious [3.7K]
The answer is 176 because 86+86=176
4 0
3 years ago
PRS is isosceles with RP RS RQ is drawn such that it bisects PRS What additional fact can be used to prove PRQ SRQ by Sas in ord
SOVA2 [1]

Answer:

\frac{PQR}{SQR}

Step-by-step explanation:

An isosceles triangle has two equal sides and the two opposite angles to the sides to be equal.

Given that; RP = RS, RQ and PS are common,

RP = SQ (opposite sides of parallelogram RPQS)

PQ = RS (opposite sides of parallelogram RPQS)

ΔRPS = ΔQPS (congruence property)

Thus comparing triangles PQR and SQR,

\frac{PQ}{SQ} = \frac{PR}{SR} (similarity property)

<PRS = <PRQ + <SRQ (bisection of included <PRS)

<PQS = <PQR + <SQR (similatity property to <PRS)

\frac{PRQ}{SRQ}  = \frac{SQR}{PQR} (congruence property)

But, SRQ = PQR

So that;

       \frac{PRQ}{SQR}

Therefore by Side-Angle-Side (SAS), the required additional fact is:  \frac{PRQ}{SQR}

8 0
3 years ago
Plzzzzzzzzzzzz help i'm doing a dcp
kramer
I believe its the third line correct me if im worng
6 0
3 years ago
Read 2 more answers
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