Answer:
the maximum speed of the ball is 12.65 m/s
Explanation:
Given;
mass of the ball, m = 40 g = 0.04 kg
spring constant, k = 25 N/m
Apply the principle of conservation of energy;
The Elastic potential energy of the spring will be converted into Kinetic of the ball;
Therefore, the maximum speed of the ball is 12.65 m/s
Answer:
Boeing
if im wrong sue me ¯\_(ツ)_/¯
<u>Answer:</u>
The force on the 2.00-uC charge is
<u>Explanation:</u>
We know that force between two charges is given by Coulomb’s law,
Where k = Coulomb’s constant =
And q1 and q2 are the charges given to be = -4.00-uC and 2.00-uC charges
And r = distance between the charges = 20 cm = 0.2 m
Substituting the given values in the formula we get force applied on charge,
F = attractive force which is the required answer.
Answer:
If energy is conserved, then the sum of the potential energy and the kinetic energy is a constant.
Assuming the proton starts from rest, so it's kineitc energy is zero, but it has a potential energy, PE equal to:
PE = qV
where q =1.6 x 10^-19 C
and V = 1.00 V
Assuming the proton no longer experiences the potential energy and it is all converted to kinetic energy then:
PE* = 0,
KE* = 1/(2mv^2)
Now since
PE + KE = Total energy =PE* + KE*
Therefore,
qV + 0 = 0 + 1/2mv^2
Or
KE = qV = 1.6 10^-19 J