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ddd [48]
2 years ago
12

What is the speed of light in a vacuume?

Physics
1 answer:
-Dominant- [34]2 years ago
5 0

The speed of light in vacuum is exactly

299,792,458 meters per second.

That's so exact that it's the official scientific definition of a "meter".

The number doesn't t change even if the flashlight or other light source is moving.

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A rolling ball will eventually stop rolling. Which describes one reason why this happens?
Nata [24]
B is the correct answer.

A is incorrect because energy is neither created nor destroyed.

C is incorrect because kinetic energy would keep the ball rolling, so that would not make sense.
7 0
3 years ago
A ball is thrown vertically down from the edge of a cliff with a speed of 4 m/s,
Serhud [2]
By using the equation speed = distance/time we can solve for distance. The speed is 4 m/s and the time is 12 seconds. We need to rearrange the equation to Speed * Time = distance. 4(12) = 48; 48 = distance. The cliff is 48 meters high.
3 0
2 years ago
The Mariana Trench is best known for its
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The answer is A) depth.
7 0
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Atoms form chemical bonds using:
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A electrons in the innermost energy level

7 0
2 years ago
ball dropped from top of 50m high cliff stone thrown straight up from bottom with speed of 24. they collide. how far above base
Tresset [83]

Answer:

28.73 m from the base of the cliff collide happen

Explanation:

Equation for ball dropped from 50 cliff is reaches distance x in t seconds isi given by

x=ut+\frac{1}{2} at^2\\\\x= 0 \times t+\frac{1}{2} gt^2 =\frac{1}{2} gt^2......(1)

stone is thrown up from the bottom with speed u=24 m/s . it reaches distance y when stone collide with ball.(g is negative here)

y=24t-\frac{1}{2} gt^2.............(2)

we know that total distance traveled by ball and stone is 50 m

x+y=50 m

adding equation 1 and 2, we get time t

x+y=\frac{1}{2} gt^2+24t-\frac{1}{2}gt^2\\50=24t\\t=2.083 s

substitute this time in equation 2, we can get the required distance where they collide

y=24t-\frac{1}{2} gt^2\\y=24\times 2.083-\frac{1}{2}\times  9.8\times 2.083^2\\y=28.73 m

28.73 m from the base of the cliff collide happen

7 0
3 years ago
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