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stiv31 [10]
3 years ago
10

A typical running track is an oval with 74-mm-diameter half circles at each end. A runner going once around the track covers a d

istance of 400 mm . Suppose a runner, moving at a constant speed, goes once around the track in 1 minmin 40 s.What is her centripetal acceleration during the turn at each end of the track?
Physics
1 answer:
lisabon 2012 [21]3 years ago
6 0

The centripetal acceleration a is 4.32 \times 10^-4 m/s^2.

<u>Explanation:</u>

The speed is constant and computing the speed from the distance and time for one full lap.

Given, distance = 400 mm = 0.4 m,       Time = 100 s.

Computing the v = 0.4 m / 100 s

                         v = 4 \times 10^-3 m/s.

radius of the circular end r = 37 mm = 0.037 m.

            centripetal acceleration a = v^2 / r

                                                        = (4 \times 10^-3)^2 / 0.037

                                                    a = 4.32 \times 10^-4 m/s^2.

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Answer:

she used force to swing her ball all way back

Explanation:

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A student was asked to push a large box down the hallway about 35 meters. the task took the student five minutes and a force of
zaharov [31]
Rate of work or Power done by the student can be computed with below formulas.
1. Formula for Work
Work = Force x distance
Force or F = Force applied to the object 
distance or d = displacement

2. Formula for Power
P = Work done / Time it was done or completed

Substituting the values we have,
Work or Work done = 150 N x 35 meters = 5250 J (unit of work).

Lastly computing for the rate we have,
Power or rate of work = 5250 J / 300 seconds (or 5 min) = 17.5 Joule/S or Watts

Answer is 17.5 watts

5 0
3 years ago
A rescue airplane is diving at an angle of 37º below the horizontal with a speed of 250 m/s. It releases a survival package when
alisha [4.7K]

Answer:

<em>The correct option is 1.  720 m</em>

Explanation:

<u>Projectile Motion</u>

When an object is launched in free air (no friction) with an initial speed vo at an angle \theta, it describes a curve which has two components: one in the horizontal direction and the other in the vertical direction. The data provided gives us the initial conditions of the survival package's launch.

\displaystyle V_o=250\ m/s

\displaystyle \theta =-37^o

The initial velocity has these components in the x and y coordinates respectively:

\displaystyle V_{ox}=250\ cos(-37^o)=199.7\ m/s

\displaystyle V_{oy}=250\ sin(-37^o)=-150.5\ m/s

And we know the plane has an altitude of 600 m, so the package will reach ground level when:

\displaystyle y=-600\ m

The vertical distance traveled is given by:

\displaystyle y=V_{oy}\ t-\frac{g\ t^2}{2}=-600

We'll set up an equation to find the time when the package lands

\displaystyle -150.5t-4.9\ t^2=-600

\displaystyle -4.9\ t^2-150.5\ t+600=0

Solving for t, we find only one positive solution:

\displaystyle t=3.6\ sec

The horizontal distance is:

\displaystyle x=V_{ox}.t=199.7\times3.6=720\ m

The correct option is 1.  720 m

6 0
3 years ago
A 1.60 m cylindrical rod of diameter 0.450 cm is connected to a power supply that maintains a constant potential difference of 1
frosja888 [35]

The question is incomplete! Complete question along with answer and step by step explanation is provided below.

Question:

A 1.60 m cylindrical rod of diameter 0.450 cm is connected to a power supply that maintains a constant potential difference of 12.0 V across its ends, while an ammeter measures the current through it. You observe that at room temperature (20.0 ∘C) the ammeter reads 18.4 A , while at 92.0 ∘C it reads 17.4 A . You can ignore any thermal expansion of the rod.

a) Find the resistivity and for the material of the rod at 20° C .

b) Find the temperature coefficient of resistivity at 20° C for the material of the rod.

Given Information:

Room temperature = T₀ = 20° C

Temperature = T = 92° C

Current at 20° C = I₀ = 18.4 A

Current at 92° C = I = 17.4 A

Voltage = V = 12 V

Length = L = 1.60 m

Diameter = d = 0.450 cm = 0.0045 m

Required Information:

Resistivity of the material at 20° C = ρ = ?

Temperature coefficient of resistivity at 20° C = α = ?

Answer:

Resistivity of the material at 20° C = 2.062x10⁻⁶ Ω.m

Temperature coefficient of resistivity at 20° C = 7.986x10⁻⁴ per °C

Explanation:

a) We want to find out the resistivity of the material at 20° C

The resistivity of any material can be found using,

ρ = R₀A/L

Where R₀ is the resistance of the rod at 20° C, A is the area of rod and L is the length of the cylindrical rod.

We also know that area is given by

A = πr²

where r = d/2 = 0.0045/2 = 0.00225 m

A = π(0.00225)²  

A = 5.062⁻⁶ m²

We know that resistance of the material is given by

R₀ = V/I₀

R₀ = 12/18.4

R₀ = 0.6521 Ω

Therefore, the resistivity of the material is

ρ = R₀A/L

ρ = (0.6521*5.062⁻⁶)/1.60

ρ = 2.062x10⁻⁶ Ω.m

b) We want to find out the temperature coefficient of resistivity of the rod at 20° C

The temperature coefficient of resistivity is given by

α = R/R₀ - 1/(T - T₀)

Where R is the resistance of the rod at 90° C

R = V/I

R = 12/17.4

R = 0.6896 Ω

α = R/R₀ - 1/(T - T₀)

α = (0.6896/0.6521) - 1/(92° - 20°)

α = 0.0575/72°

α = 0.000798 per °C

α = 7.986x10⁻⁴ per °C

3 0
3 years ago
Read 2 more answers
A very long straight current-carrying wire produces a magnetic field of 20 mt at a distance d from the wire. to measure a field
padilas [110]

The distance covered is 4d.

<h3>What is the distance?</h3>
  • Distance is a measure of how far apart two objects or locations are using numbers.
  • The distance can refer to a physical length or an estimate based on other factors in both daily language and physics (e.g. "two counties over").
  • The terms "distance from A to B" and "distance from B to A" are frequently used interchangeably.
  • A distance function or metric is a technique to describe what it means for components of space to be "near to" or "far away" from each other in mathematics.
  • It is a generalization of the idea of physical distance. Distance is a non-numerical unit of measurement in psychology and the social sciences; psychological distance is the separation of an object from itself along dimensions including time, space, and isolation.

We know that

the magnetic field is inversely proportional to distance.

\dfrac{B_1}{B_2} = \dfrac{D_2}{D_1}

\dfrac{20}{5} = \dfrac{D_2}{d}

D_2 = 4d

To learn more about distance with the given link

brainly.com/question/15172156

#SPJ4

3 0
2 years ago
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