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jeka57 [31]
3 years ago
10

At a​ little-known vacation​ spot, taxi fares are a bargain. A 14-mile taxi ride takes 16 minutes and costs $11.20. You want to

find the cost of a ​37-mile taxi ride. What unit price do you​ need?

Mathematics
2 answers:
satela [25.4K]3 years ago
7 0

Answer:

$29.60 is the correct answer hope this helps

sergeinik [125]3 years ago
6 0

Answer:

$29.60

Step-by-step explanation:

$11.20/14 miles = $0.80 per mile

$0.80 x 37 = $29.60

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The sides of a triangle have lengths 3, 25, and 27. What kind of triangle is it ?
Andrew [12]

Answer:

Step-by-step explanation:

it's obtuse the sides are to wide

3 0
2 years ago
A certain make of car is available in 5 body types, 4 colors, and 3 kinds of upholstery. How many cars would a dealer have to ke
NeX [460]
So there's 5 body types each with 4 colors. 5x4 is 20. For each of these 20 cars there is 3 kinds of upholstery. 20x3 is 60. Therefore, the dealer would need a minimum of 60 cars to show his complete line. Hope this helped!
7 0
3 years ago
Read 2 more answers
Select ALL the correct answers.
Marina CMI [18]

Answer:

The median of A is the same as the median of B.

The interquartile range of B is greater than the interquartile range of A.

Step-by-step explanation:

Given that:

A = number of runs allowed in first 9 games

A = {1, 4, 2, 2, 3, 1, 1, 2, 1}

Rearranging A : 1, 1, 1, 1, 2, 2, 2, 3, 4

Median A = 1/2(n + 1) th term

Median A = 1/2(10) = 5th term = 2

Q1 of A = 1/4(10) = 2.5th term = (1 + 1)/ 2 = 1

Q3 of A = 3/4(10) = 7.5th term = (2+3)/2 = 2.5

Interquartile range = Q3 - Q1 = 2.5 - 1 = 1.5

Number of runs allowed in 10th game = 9

B = {1, 4, 2, 2, 3, 1, 1, 2, 1, 9}

Rearranging B = 1, 1, 1, 1, 2, 2, 2, 3, 4, 9

Median A = 1/2(n + 1) th term

Median A = 1/2(11) = 5.5th term = (2+2)/2 = 2

Q1 of A = 1/4(11) = 2.75th tetm = (1 + 1)/ 2 = 1

Q3 of A = 3/4(11) = 8.25th term = (3+4)/2 = 3.5

Interquartile range = Q3 - Q1 = 3.5 - 1 = 2.5

Median A = 2 ; median B = 2

IQR B = 2.5 ; IQR A = 1.5 ; IQR B > IQR A

7 0
3 years ago
Write the equation for the absolute value function graphed below
Jobisdone [24]

Answer:

y = 2|x+3| -2

Step-by-step explanation:

1) slope = rise/run= 4/2 =2 - for the right line

2) y = 2|x| initial graph

3) It  is moved 3 units left

y = 2|x+3|

4) It moved 2 units down

y = 2|x+3| -2

3 0
3 years ago
An article describes an experiment to determine the effectiveness of mushroom compost in removing petroleum contaminants from so
alexgriva [62]

Solution :

Let p_1 and p_2  represents the proportions of the seeds which germinate among the seeds planted in the soil containing 3\% and 5\% mushroom compost by weight respectively.

To test the null hypothesis H_0: p_1=p_2 against the alternate hypothesis  H_1:p_1 \neq p_2 .

Let \hat p_1, \hat p_2 denotes the respective sample proportions and the n_1, n_2 represents the sample size respectively.

$\hat p_1 = \frac{74}{155} = 0.477419

n_1=155

$p_2=\frac{86}{155}=0.554839

n_2=155

The test statistic can be written as :

$z=\frac{(\hat p_1 - \hat p_2)}{\sqrt{\frac{\hat p_1 \times (1-\hat p_1)}{n_1}} + \frac{\hat p_2 \times (1-\hat p_2)}{n_2}}}

which under H_0  follows the standard normal distribution.

We reject H_0 at 0.05 level of significance, if the P-value or if |z_{obs}|>Z_{0.025}

Now, the value of the test statistics = -1.368928

The critical value = \pm 1.959964

P-value = $P(|z|> z_{obs})= 2 \times P(z< -1.367928)$

                                     $=2 \times 0.085667$

                                     = 0.171335

Since the p-value > 0.05 and $|z_{obs}| \ngtr z_{critical} = 1.959964$, so we fail to reject H_0 at 0.05 level of significance.

Hence we conclude that the two population proportion are not significantly different.

Conclusion :

There is not sufficient evidence to conclude that the \text{proportion} of the seeds that \text{germinate differs} with the percent of the \text{mushroom compost} in the soil.

8 0
3 years ago
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