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Alex787 [66]
1 year ago
8

You are going to paint a six-sector spinner. There are 4 colors to choose from. How many different ways can you paint the spinne

r if each color can be used more than once and no two adjacent sectors can be the same color?
Mathematics
1 answer:
emmainna [20.7K]1 year ago
4 0

Using the Fundamental Counting Theorem, it is found that there are 648 ways to paint the spinner.

<h3>What is the Fundamental Counting Theorem?</h3>

It is a theorem that states that if there are n things, each with n_1, n_2, \cdots, n_n ways to be done, each thing independent of the other, the number of ways they can be done is:

N = n_1 \times n_2 \times \cdots \times n_n

In this problem, we have that the first sector can be painted in any of the 4 colors, the others until the 5th can be painted in 3 colors(not the adjacent), and the sixth in only 2, as it is adjacent to both the 5th and the 1st sectors, hence:

n_1 = 4, n_2 = n_3 = n_4 = n_5 = 3, n_6 = 2

Hence the number of ways is given by:

N = 4 x 3 x 3 x 3 x 3 x 2 = 648.

More can be learned about the Fundamental Counting Theorem at brainly.com/question/24314866

#SPJ1

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