May someone please help me out on this question

Mathematics

1 answer:

NISA [10]3 years ago

8 0

Answer:

Step-by-step explanation:

It's hard to see but when x is 6, y is 4.5. Just plug that into each equation and see which one is correct.

$x^{2} =8y\\x=6;y=4.5\\6^{2} =8(4.5)\\36=36$

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What is the greatest common factor of 8x and 40

Novay_Z [31]

The GCF of 8x and 40 is 8

6 0

3 years ago

Can someone help me with these questions please?

kotykmax [81]

Step-by-step explanation:

You can solve systems of equations using either substitution or elimination. For these problems, I recommend elimination. I'll do the first one as an example.

-3x + 16y = 9

-4x + 8y = 12

Multiply the second equation by -2.

8x − 16y = -24

Add to the first equation (notice the y's cancel out).

(-3x + 16y) + (8x − 16y) = 9 − 24

5x = -15

Solve for x.

x = -3

Now you can plug this into either equation to find y.

-3(-3) + 16y = 9

9 + 16y = 9

y = 0

The solution is (-3, 0).

3 0

3 years ago

In an international film festival, a penal of 11 judges is formed to judge the best film. At last two films FA and FB were consi

valentina_108 [34]

Answer:

The answer is "0.4329 ".

Step-by-step explanation:

P( three in favor of FA)

Select 3 out of 6 FA supporters then select 2 out of 5 FB supportive judges

$=\frac{^{6}_{C_{3}}\times ^{5}_{C_{2}}}{^{11}_{C_{5}}}\\\\=\frac{\frac{6!}{3!(6-3)!}\times \frac{5!}{2!(5-2)!}}{\frac{11!}{5!(11-5)!}}\\\\=\frac{\frac{6!}{3! \times 3!}\times \frac{5!}{2! \times 3!}}{\frac{11!}{5! \times 6!}}\\\\=\frac{\frac{6 \times 5 \times 4 \times 3!}{3 \times 2 \times 1\times 3!}\times \frac{5 \times 4 \times 3!}{2 \times 1 \times 3!}}{\frac{11 \times10 \times 9 \times 8 \times 7 \times 6! }{5 \times 4 \times 3 \times 2 \times 1 \times 6!}}\\\\$

$=\frac{ (5 \times 4) \times(5 \times 2)}{(11 \times 3 \times 2 \times 7 )}\\\\=\frac{ 20 \times 10 }{(11 \times 42)}\\\\=\frac{ 200 }{462}\\\\=\frac{100 }{231}\\\\=0.4329$