Answer : The pH of the solution is, 5.24
Explanation :
First we have to calculate the volume of 
Formula used :

where,
are the initial molarity and volume of
.
are the final molarity and volume of
.
We are given:

Putting values in above equation, we get:

Now we have to calculate the total volume of solution.
Total volume of solution = Volume of
+ Volume of 
Total volume of solution = 160.0 mL + 1086.79 mL
Total volume of solution = 1246.79 mL
Now we have to calculate the Concentration of salt.

Now we have to calculate the pH of the solution.
At equivalence point,
![pOH=\frac{1}{2}[pK_w+pK_b+\log C]](https://tex.z-dn.net/?f=pOH%3D%5Cfrac%7B1%7D%7B2%7D%5BpK_w%2BpK_b%2B%5Clog%20C%5D)
![pOH=\frac{1}{2}[14+4.87+\log (0.0437)]](https://tex.z-dn.net/?f=pOH%3D%5Cfrac%7B1%7D%7B2%7D%5B14%2B4.87%2B%5Clog%20%280.0437%29%5D)


Thus, the pH of the solution is, 5.24