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KATRIN_1 [288]
3 years ago
9

_c h 3 c h 2 c o o h+ _0 2 -》 _h 2 o + co2 how many molecules of o2 are required for the complete combustion of 6 moles of propa

noic acid
Chemistry
1 answer:
lesya692 [45]3 years ago
3 0

Answer:

21 molecules of oxygen.

Explanation:

The balanced equation is

2CH3CH2COOH + 7O2 ----->  6CO2 +  6H2O.

So 2 molecules of propanoic acid require   7 moles of oxygen.

Therefore 6 molecules require 7/2 * 6 = 21 molecules of oxygen.

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andriy [413]
Okay.. so I guess this is how it goes:

1. Rainforest
2. Temperate deciduous
3. Marine
4. Taiga
5. Tundra

Pls don't completely rely on it, this is my best guess and it's probably right except with Marine life and temperature deciduous. 70% I feel like it would temperate then marine. But check with urself again. Hope this helped..
5 0
2 years ago
109kPa = _________ mm Hg
LekaFEV [45]

817.567 mm hg the answer for number 2

3 0
3 years ago
Which of the following is a likely mechanism for the reaction CH3Cl + OH- ----> CH3OH + Cl-, which is first order with respec
abruzzese [7]

Answer:

A one-step mechanism involving a transition state that has a carbon partially bonded to both chlorine and oxygen

Explanation:

The compound CH3Cl is methyl chloride. This is a nucleophilic substitution reaction that proceeds by an SN2 mechanism. The SN2 mechanism is a concerted reaction mechanism. This means that the departure of the leaving group is assisted by the incoming nucleophile. The both species are partially bonded to opposite sides of the carbon atom in the transition state.

Recall that an SN2 reaction is driven by the attraction between the negative charge of the nucleophile (OH^-) and the positive charge of the electrophile (the partial positive charge on the carbon atom bearing the chlorine leaving group).

4 0
3 years ago
Electrochemistry - Equilibrium
Ipatiy [6.2K]

Answer:

Explanation:

The relation between equilibrium constant and Ecell is given below .

E⁰cell = (RT / nF ) lnK  , F is faraday constant T is 273 + 25 = 298 K

E⁰cell  =  1.46 - 1.21 = .25 V

n = 2

Putting the values

.25 = (8.314 x 298  lnK) / (2 x 96485 )

lnK = 19.47

K = 2.85 x 10⁸

2 )

Change in free energy Δ G

Δ G ⁰ = nE⁰ F

n = 4

E⁰ = .4 + .83 = 1.23 V

Δ G ⁰= 4 x 1.23 x 96485

= 474706 J / mol

3 )

E⁰cell = (RT / nF ) lnK

n = 2

1.78 = 8.314 x 298  lnK / 2 x 96485

lnK = 138.638

K = 1.62 x 10⁶⁰

8 0
3 years ago
The elements found in Group 2A, from top to bottom, include beryllium, magnesium, calcium, strontium, and barium. Which of these
pashok25 [27]
Answer is beryllium.

The electronegativity trend is that it increases from left to right in a period and from bottom to top in a group. This is why fluorine has the highest electronegativity out of all the elements. So since beryllium is at the very top of the group, it has the highest electronegativity
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3 years ago
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