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Art [367]
2 years ago
12

Practice

Chemistry
1 answer:
krek1111 [17]2 years ago
4 0

The number of significant figures in each of the following numbers are as follows:

  • 640 cm³ - number of significant figures: 2
  • 200.0 mL - number of significant figures: 4
  • 0.5200 g - number of significant figures: 4
  • 1.005 kg - number of significant Figures: 4
  • 10,000 L - number of significant figures: 1
  • 20.900 cm - number of significant figures: 5

<h3>What is significant figures?</h3>

Significant figures are those figures that are meaningful with respect to the precision of a measurement.

In other words, a digit that is nonzero, followed by a nonzero digit,or (for trailing zeroes) justified by the precision of the derivation or measurement is a significant figure.

Based on the question, the number of significant figures in each of the following numbers are as follows:

  • 640 cm³ - number of significant figures: 2
  • 200.0 mL - number of significant figures: 4
  • 0.5200 g - number of significant figures: 4
  • 1.005 kg - number of significant figures: 4
  • 10,000 L - number of significant figures: 1
  • 20.900 cm - number of significant figures: 5

Learn more about significant figures at: brainly.com/question/14359464

#SPJ1

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How many liters of ammonia (NH3), at 3.2 atm and 23C, must be used to produce of 2.65 grams of calcium hydride (CaH2). 6 Ca(s)
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Answer:

The answer to your question is    V = 0.32 L

Explanation:

Data

Volume of NH₃ = ?

P = 3.2 atm

T = 23°C

mass of CaH₂ = 2.65 g

Balanced chemical reaction

               6Ca  +  2NH₃   ⇒   3CaH₂  +  Ca₃N₂

Process

1.- Convert the mass of CaH₂ to moles

-Calculate the molar mass of CaH₂

 CaH₂ = 40 + 2 = 42 g

                             42 g ------------------ 1 mol

                              2.65 g --------------  x

                              x = (2.65 x 1)/42

                              x = 0.063 moles

2.- Calculate the moles of NH₃

                     2 moles of NH₃ --------------- 3 moles of CaH₂

                      x                        --------------- 0.063 moles

                                x = (0.063 x 2) / 3

                                x = 0.042 moles of NH₃

3.- Convert the °C to °K

Temperature = 23°C + 273

                      = 296°K

4.- Calculate the volume of NH₃

-Use the ideal gas law

              PV = nRT

-Solve for V

                V = nRT / P

-Substitution

                V = (0.042)(0.082)(296) / 3.2

-Simplification

               V = 1.019 / 3.2

-Result

               V = 0.32 L

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