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Elodia [21]
2 years ago
13

Can anyone please help me with this question?

Mathematics
1 answer:
adelina 88 [10]2 years ago
4 0

Answer:

15 cm

Step-by-step explanation:

A= base x height

\frac{1500cm^{3} }{100 {cm}^{2} }  \\  = 15cm

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Find the x-intercepts, use the zero product property, r(r+7)=0
UkoKoshka [18]

9514 1404 393

Answer:

  r = 0

  r = -7

Step-by-step explanation:

There is no x in the equation, hence there are no x-intercepts.

__

If we assume you want the values of r that satisfy the equation, the zero product property tells you they will be the values that make the factors zero.

The factors are r and (r+7).

The factor r is zero when ...

  r = 0

The factor (r+7) is zero when ...

  r +7 = 0   ⇒   r = -7

The "x-intercepts" are r=0 and r=-7.

4 0
2 years ago
Write as a single fraction in its simplest form.
yaroslaw [1]

\dfrac{4}{3x-5} + \dfrac{x+2}{x-1}\\\\\\=\dfrac{4(x-1) + (x+2)(3x-5)}{(3x-5)(x-1)}\\\\\\=\dfrac{4x-4 + 3x^2 -5x +6x -10}{(3x-5)(x-1)}\\\\\\=\dfrac{3x^2 +5x-14}{(3x-5)(x-1)}

5 0
2 years ago
FIND THE GCF. Mathematics
Rom4ik [11]

The G.C.F of the given algebraic expression is; ⁴⁹/₆a xy

<h3>What is the G.C.F (Greatest Common Factor)?</h3>

The greatest common factor (GCF or GCD or HCF) of a set of whole numbers is the largest positive integer that divides evenly into all numbers with zero remainder. For example, for the set of numbers 18, 30 and 42 the GCF = 6.

We are given the algebraic expression;

(3 x y * 4x²y * ¹/₁ * 5x³y ^ z * 4)7a * 1/1 * 7*6

Expanding this further gives;

⁴⁹/₆a((3xy * 4x²y * 20x³y ^ z )

Now, the GCF of the terms inside the bracket would be x y. Thus, expanding the GCF  we have;

⁴⁹/₆a xy((3 * 4x * 20x²y^(z - 1))

Read more about G.C.F at; brainly.com/question/219464

#SPJ1

5 0
1 year ago
A right triangle has a leg of 12 cm and a hypotenuse of 16 cm what is the length of the other leg
Oksi-84 [34.3K]
The length of the other leg is 12 cm
6 0
3 years ago
What are the roots of the quadratic equation 2x2+7x+4=0? Select all that apply.
skad [1K]

Answer:

option A and B

x=\frac{-7+\sqrt{17}} {4}

and

x=\frac{-7-\sqrt{17}} {4}

Step-by-step explanation:

we have

2x^2+7x+4=0

The formula to solve a quadratic equation of the form

ax^{2} +bx+c=0

is equal to

x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}

in this problem we have

2x^2+7x+4=0

so

a=2\\b=7\\c=4

substitute in the formula

x=\frac{-7\pm\sqrt{7^{2}-4(2)(4)}} {2(2)}

x=\frac{-7\pm\sqrt{17}} {4}

so

x=\frac{-7+\sqrt{17}} {4}

and

x=\frac{-7-\sqrt{17}} {4}

7 0
2 years ago
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