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3 years ago

Can someone help me please

Mathematics

1 answer:

rusak2 [61]3 years ago

3 0

9514 1404 393

Answer:

see attached

Step-by-step explanation:

The sum is formed by adding corresponding elements. For example, the lower right element (row 3, col 3) of the sum is 5+4 = 9

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Can anyone help me with this?

Vanyuwa [196]

Answer:

-2.5°F

Step-by-step explanation:

-12 - 48 = -60

-60/24 = -2.5°F

7 0

3 years ago

Let a be a rational number and b be an irrational number. Which of the following are true statements?(there is more than 1 answe

kramer

A.) the sum of a and b is never rational.
This is a true statement. Since an irrational umber has a decimal part that is infinite and non-periodical, when you add a rational number to an irrational number, the result will have the same infinite non periodical decimal part, so the new number will be irrational as well.

B.) The product of a and b is rational
This one is false. Zero is a rational number, and when you multiply an irrational number by zero, the result is always zero.

C.) b^2 is sometimes rational
This one is true. When you square an irrational number that comes from a square root like $\sqrt{2}$ , you will end with a rational number: $( \sqrt{2} )^{2}=2$ , but, if you square rationals from different roots than square root like $\sqrt[3]{2}$ , you will end with an irrational number: $\sqrt[3]{2^{2} } = \sqrt[3]{2}$ .

D.) a^2 is always rational
This one is false. If you square a rational number, you will always end with another rational number.

E.) square root of a is never rational
This one is false. The square root of perfect squares are always rational numbers: $\sqrt{64} =8$ , $\sqrt{16} =4$ ,...

F.) square root of b is never rational
This one is true. Since the square root of any non-perfect square number is irrational, and all the irrational numbers are non-perfect squares, the square root of an irrational number is always irrational.

We can conclude that given that a is a rational number and b be an irrational number, A, C, D, and F are true statements.

4 0

3 years ago

Determine what type of model best fits the given situation:

lyudmila [28]

Let value intially be = P

Then it is decreased by 20 %.

So 20% of P = $\frac{20}{100} \times P = 0.2P$

So after 1 year value is decreased by 0.2P

so value after 1 year will be = P - 0.2P (as its decreased so we will subtract 0.2P from original value P) = 0.8P-------------------------------------(1)

Similarly for 2nd year, this value 0.8P will again be decreased by 20 %

so 20% of 0.8P = $\frac{20}{100} \times 0.8P = (0.2)(0.8P)$

So after 2 years value is decreased by (0.2)(0.8P)

so value after 2 years will be = 0.8P - 0.2(0.8P)

taking 0.8P common out we get 0.8P(1-0.2)

= 0.8P(0.8)

$=P(0.8)^{2}$ -------------------------(2)

Similarly after 3 years, this value $P(0.8)^{2}$ will again be decreased by 20 %

so 20% of $P(0.8)^{2} \frac{20}{100} \times P(0.8)^{2} = (0.2)P(0.8)^{2}$

So after 3 years value is decreased by $(0.2)P(0.8)^{2}$

so value after 3 years will be = $P(0.8)^{2} - (0.2)P(0.8)^{2}$

taking $P(0.8)^{2}$ common out we get $P(0.8)^{2}(1-0.2)$

$P(0.8)^{2}(0.8)$

$P(0.8)^{3}$ -----------------------(3)

so from (1), (2), (3) we can see the following pattern

value after 1 year is P(0.8) or $P(0.8)^{1}$

value after 2 years is $P(0.8)^{2}$

value after 3 years is $P(0.8)^{3}$

so value after x years will be $P(0.8)^{x}$ ( whatever is the year, that is raised to power on 0.8)

So function is best described by exponential model

$y = P(0.8)^{x}$ where y is the value after x years

so thats the final answer

3 0

3 years ago

-3(4x+5) please help

Natasha_Volkova [10]

Answer:
-12x-15
explanation:
you multiply -3 by 4x, gives u -12x and then you multiply -3 by 15 which gives you -15
then you put it in an equation
-12x-15

7 0

3 years ago

3p - 2(p-4) = 7p + 6

Serggg [28]

For this case we must find the value of the variable "p" of the following equation:

$3p-2 (p-4) = 7p + 6$