All categories

3 years ago

Which change most likely occurs when the kinetic energy of water vapor decreases during condensation?

Chemistry

1 answer:

mylen [45]3 years ago

6 0

Answer:

When the kinetic energy of water vapor decreases during condensation, <u>slowly moving particles near the cool surface condense.</u>

Explanation:

The change of state from a gas to a liquid is condensation. Liquid molecules which have this certain kinetic energy threshold escape from the surface and become vapor. As a result, the remaining liquid molecules now have lower kinetic energy. The temperature of the remaining liquid decreases as evaporation occurs.

The air that surrounded it cooled the cold can or glass. When you're cooling off .They lose kinetic energy, a gas. The particles move more slowly as they move, the attractions between them cause the formation of droplets of liquid. Condensed With, when hot air containing water vapor reaches water, water also forms. Cold surface touch, such as a glass of ice or soil that has a cold surface refrigerated throughout the night.

You might be interested in

Molecules in 2 moles of carbon dioxide<br>

Maksim231197 [3]

Answer:

HAVE A NICE DAY OK

I GOT UR ANSWER

5 0

3 years ago

CAN SOMEONE HELP ME!!!

NISA [10]

Answer:

I think D

Explanation:

4 0

3 years ago

Read 2 more answers

What is the area of triangle ABC with vertices A(x¹,y¹), B(x²,y²)and C (x³,y³)??????????<br>

AlexFokin [52]

Answer:

$Area = \frac{1}{2}|x_1(y_2 - y_3)+x_2(y_3 - y_1)+x_3(y_1 - y_2)|$

$Area = 2\ units^2$

Explanation:

Given

$A = (x_1,y_1)$

$B = (x_2,y_2)$

$C = (x_3,y_3)$

Required

Determine the area

The area of a triangle is :

$Area = \frac{1}{2}|A_x(B_y - C_y) + B_x(C_y - A_y) + C_x(A_y - B_y)|$

By substituting values for the x and y coordinates of A, B and C;

We have:

$Area = \frac{1}{2}|x_1(y_2 - y_3)+x_2(y_3 - y_1)+x_3(y_1 - y_2)|$

So:

For instance

$A = (0,3)$

$B= (2,1)$

$C = (2,3)$

The area is:

$Area = \frac{1}{2}|0(1-3) + 2(3-3) + 2(3-1)|$

$Area = \frac{1}{2}| 2*0 + 2*2|$

$Area = \frac{1}{2}| 0 + 4|$

$Area = \frac{1}{2}|4|$

$Area = \frac{1}{2} * 4$

$Area = 2\ units^2$

7 0

3 years ago

Molarity to percent by mass. Convert 1.672 mol/L MgCl2(aq) solution to percent by mass of MgCl2 in the solution. The solution de

nignag [31]

Answer:

$\%m/m=14\%$

Explanation:

Hello!

In this case, since the molarity of magnesium chloride (molar mass = 95.211 g/mol) is 1.672 mol/L and we know the density of the solution, we can first compute the concentration in g/L as shown below:

$[MgCl_2]=1.672\frac{molMgCl_2}{L}*\frac{95.211gMgCl_2}{1molMgCl_2}=159.2\frac{gMgCl_2}{L}$