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sergey [27]
3 years ago
9

Balance the following redox reaction in acidic solution: H+(aq)+Zn(s)→H2(g)+Zn2+(aq)

Chemistry
1 answer:
erma4kov [3.2K]3 years ago
5 0
2H⁺(aq) + Zn(s) ----> H2(g) + Zn²⁺(aq)

2H⁺(aq) +2e⁻ ----->H2(g)            reduction
<span><u>Zn(s)            ------>Zn²⁺ +2e⁻      oxidation</u>
</span>2H⁺(aq) + Zn(s) -----> H2(g) + Zn²⁺
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A sample of wood from the remains of a ship was found to contain 40.0% of C-14 as of ordinary wood found now. If the half-life p
kondaur [170]

Answer:

7628 y

Explanation:

Carbon-14 is radioactive and it follows the first-order kinetics for a radioactive decay. The first-order kinetics may be described by the following integrated rate law:

ln(\frac{[A]_t}{[A]_o})=-kt

Here:

[A]_t is the mass, moles, molarity or percentage of the material left at some time of interest t;

[A]_o is the mass, moles, molarity or percentage of the material initially, we know that initially we expect to have 100 % of carbon-14 before it starts to decay;

k = \frac{ln(2)}{T_{\frac{1}{2}}} is the rate constant;

t is time.

The equation becomes:

ln(\frac{[A]_t}{[A]_o})=-\frac{ln(2)}{T_{\frac{1}{2}}}t

Given:

\frac{[A]_t}{[A]_o} = \frac{40.0 %}{100.0 %}

T_{\frac{1}{2}} = 5770 y

Solve for time:

t = -\frac{ln(\frac{[A]_t}{[A]_o})\cdot T_{\frac{1}{2}}}{ln(2)}

In this case:

t = -\frac{ln(\frac{40.0\%}{100.0\%})\cdot 5770 y}{ln(2)}

t = 7628 y

3 0
3 years ago
Why is the value listed for atomic mass for each element on the periodic table not a whole number?
sweet-ann [11.9K]
A. it is an average

8 0
4 years ago
A 3.96x10^-24 M solution of compound A exhibited an absorbance of 0.624 at 238 nm in a 1.000-cm cuvet; a blank solution containi
viktelen [127]

Actual question from source:-

A 3.96x10-4 M solution of compound A exhibited an absorbance of 0.624 at 238 nm in a 1.000 cm cuvette.  A blank had an absorbance of 0.029.  The absorbance of an unknown solution of compound A was 0.375.  Find the concentration of A in the unknown.

Answer:

Molar absorptivity of compound A = 1502.53\ {Ms}^{-1}

Explanation:

According to the Lambert's Beer law:-

A=\epsilon l c

Where, A is the absorbance

 l is the path length  

\epsilon is the molar absorptivity

c is the concentration.  

Given that:-

c = 3.96\times 10^{-4}\ M

Path length = 1.000 cm

Absorbance observed = 0.624

Absorbance blank = 0.029

A = 0.624 - 0.029 = 0.595

So, applying the values in the Lambert Beer's law as shown below:-

0.595=\epsilon\times 1.000\ cm\times 3.96\times 10^{-4}\ M

\epsilon=\frac{0.595}{3.96\times 10^{-4}}\ {Ms}^{-1}=1502.53\ {Ms}^{-1}

<u>Molar absorptivity of compound A = 1502.53\ {Ms}^{-1}</u>

4 0
4 years ago
Consider the fermentation reaction of glucose: C6H12O6 → 2C2H5OH + 2CO2 A 1.00-mol sample of C6H12O6 was placed in a vat with 10
inessss [21]

Answer:

% yield = 73.48 %

Explanation:

The fermentation reaction is:

C₆H₁₂O₆  →  2C₂H₅OH + 2CO₂          

The percent yield of C₂H₅OH is given by:

\% yield = \frac{m_{E}}{m_{T}} * 100

<em>where m_{E}: is the obtained mass of C₂H₅OH = 67.7g and m_{T}: is the theoretical mass of C₂H₅OH.     </em>

The theoretical mass of C₂H₅OH is calculated knowing that 1 mol of C₆H₁₂O₆ produces 2 moles of C₂H₅OH:  

m_{T} = mol * M

<em>where M: is the molar mass of C₂H₅OH =  46.068 g/mol</em>

m_{T} = 2 moles * 46.068 g/mol = 92.136 g                

Hence, the percent yield of C₂H₅OH is:

\% yield = \frac{67.7 g}{92.136 g}*100 = 73.48 \%

I hope it helps you!                  

3 0
3 years ago
What is the minimum number of liters of co2 measured at stp needed to produce 32 grams of oxygen?
bulgar [2K]
236 I DONT KNOW I AM TOTALLY THAT IS NOT THE ANSWER
4 0
4 years ago
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