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Delvig [45]
4 years ago
7

Let X denote the voltage at the output of a microphone, and suppose that X has a uniform distribution on the interval from −1 to

1. The voltage is processed by a "hard limiter" with cutoff values −0.5 and 0.5, so the limiter output is a random variable Y related to X by Y = X if |X| ≤ 0.5, Y = 0.5 if X > 0.5, and Y = −0.5 if X < −0.5.

Mathematics
1 answer:
Naya [18.7K]4 years ago
4 0

Answer:

Step-by-step explanation:

Please kindly go through the attached file for a step by step approach to the question.

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Simplify the difference. (4w^2 – 4w – 8) – (2w^2 + 3w – 6)
Blababa [14]

Answer:

  2w^2 -7w-2

Step-by-step explanation:

(4w^2 – 4w – 8) – (2w^2 + 3w – 6)

Distribute the minus sign

(4w^2 – 4w – 8) – 2w^2 - 3w + 6

I like to line them up vertically

  4w^2 – 4w – 8

– 2w^2 - 3w + 6

-----------------------------

  2w^2 -7w-2

8 0
3 years ago
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During an experiment, Mrs. Melsoner uses an analytical scale to measure the mass of a substance. The analytical scale says she h
stich3 [128]

Answer:

hii there

The correct answer is ( D )

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7 0
3 years ago
8. Mark chose a number between 0.437 and 0.436 and multiplied it by 4. Then, he
Dvinal [7]

Answer:

y=¾(4x-20)

y=3x-15

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3 years ago
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Which of the following p values will lead us to reject the null hypothesis if the level of significance equals .05?
V125BC [204]

Answer:

So then our significance level is \alpha=0.05 and we need to remember these two conditions:

1) If the p value p_v we have enough evidence to reject the null hypothesis at the significance level given

2) If the p value p_v \geq \alpha we have enough evidence to FAIL reject the null hypothesis at the significance level given

And baed on the options we see that the only possibility would be:

d. 0.015

Step-by-step explanation:

We want to know for which value we would REJECT the null hypothesis.

So then our significance level is \alpha=0.05 and we need to remember these two conditions:

1) If the p value p_v we have enough evidence to reject the null hypothesis at the significance level given

2) If the p value p_v \geq \alpha we have enough evidence to FAIL reject the null hypothesis at the significance level given

And baed on the options we see that the only possibility would be:

d. 0.015

7 0
3 years ago
Find a quadratic polynomial with integer coefficients which has x = 2/9, ± SQRT23/9 as its real zeros.
melomori [17]

Answer:

The quadratic polynomial with integer coefficients is y = 81\cdot x^{2}-36\cdot x -19.

Step-by-step explanation:

Statement is incorrectly written. Correct form is described below:

<em>Find a quadratic polynomial with integer coefficients which has the following real zeros: </em>x = \frac{2}{9}\pm \frac{\sqrt{23}}{9}<em>. </em>

Let be r_{1} = \frac{2}{9}+\frac{\sqrt{23}}{9} and r_{2} = \frac{2}{9}-\frac{\sqrt{23}}{9} roots of the quadratic function. By Algebra we know that:

y = (x-r_{1})\cdot (x-r_{2}) = x^{2}-(r_{1}+r_{2})\cdot x +r_{1}\cdot r_{2} (1)

Then, the quadratic polynomial is:

y = x^{2}-\frac{4}{9}\cdot x -\frac{19}{81}

y = 81\cdot x^{2}-36\cdot x -19

The quadratic polynomial with integer coefficients is y = 81\cdot x^{2}-36\cdot x -19.

5 0
3 years ago
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