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lukranit [14]
3 years ago
14

You're caught running a red light on Hwy 316. Attempting to impress the skeptical patrol officer with your physics knowledge, yo

u claim that you were traveling so fast that the red light (687 nm) appeared yellow (582 nm) to you.How fast would you have been traveling (in mi/hr) if that had been the case?
If you had been traveling that fast and the light actually was yellow, what color would it have seemed to you?
Physics
1 answer:
kykrilka [37]3 years ago
3 0

Answer

given,

wavelength of the red light,λ = 687 nm

wavelength of the yellow light = 582 nm

Frequency of red light

=\dfrac{v}{\lambda}

=\dfrac{3\times 10^8}{687\times 10^{-9}}

= 4.36 x 10¹⁴ Hz

frequency of the yellow light

=\dfrac{3\times 10^8}{582\times 10^{-9}}

= 5.15 x 10¹⁴ Hz

speed of the car

f = f_o(\dfrac{c+v_r}{c})

v_r is the required speed.

5.15\times 10^{14}=4.36\times 10^{14}(\dfrac{c+v_r}{c})

v_r = 0.19 c

v_r = 0.19 x 3 x 10⁸ =5.7 x 10⁷ m/s

1 m/s = 2.23694 mile/hr

v_r = 1.27 x 10⁸ mile/hr

if the light is actually yellow

f₀ = 5.15 x 10¹⁴ Hz

f =5.15\times 10^{14}(\dfrac{c+0.19c}{c})

f = 6.13 x 10¹⁴ Hz

wavelength corresponding to this frequency is wavelength = 493.2 nm

hence, the color corresponding to this wavelength is Green.

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A 1500 kg car is approaching a hill that has a height of 12 m. As the car reaches the bottom of the hill it runs out of gas and
ICE Princess25 [194]

Answer:

No, the car will not make it to the top of the hill.

Explanation:

Let ΔX be how long the slope of the hill is, Δx be how far the car will travel along the slope of the hill, Ф be the angle the slope of the hill makes with the horizontal(bottom of the hill), ki be the kinetic energy of the car at the bottom of the hill and vi be the velocity of the car at the bottom of the hill and kf be the kinetic energy of the car when it stop moving at vf.

Since Ф is the angle between the horizontal and the slope, the relationship between the angle and the slope and the height of the hill is given by

sinФ = 12/ΔX

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ΔX = 12/sinФ

Therefore for the car to reach the top of the hill it will have to travel ΔX.

Ignoring friction the total work done is given by

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W = (kf - ki)

Since the car will come to a stop, kf = 0 J

W = -ki

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ΔX>>Δx Ф ∈ (0° , 90°)

(Note that the maximum angle Ф is 90° because the slope of a hill can never be greater ≥ 90° because that would then mean the car cannot travel uphill.)

Since the car can never travel the distance of the slope, it can never make it to the top of the hill.

3 0
3 years ago
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Nata [24]

Answer:

kinetic energy is 2, 4, 50 thirties, 2.45 into 10, raise to three Julie.

Explanation:

In the given question, we are told that what is the kinetic energy of mass M equals 0.1 kg bullet traveling at a velocity Velocity is given and 700 m/s. So we know that kinetic energy mm-hmm k equals one half m v squared. So this will be mass is given 0.1 and velocity is 700 so 700 square this is one half 0.1 in two 49 double zero, double zero. This is one-half into 49 double zero. So kinetic energy is 2, 4, 50 thirties, 2.45 into 10, raise to three Julie. This is kinetic energy. Thank you.

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The smallest unit of an element that has all of the properties of the element is a/an
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