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lukranit [14]
3 years ago
14

You're caught running a red light on Hwy 316. Attempting to impress the skeptical patrol officer with your physics knowledge, yo

u claim that you were traveling so fast that the red light (687 nm) appeared yellow (582 nm) to you.How fast would you have been traveling (in mi/hr) if that had been the case?
If you had been traveling that fast and the light actually was yellow, what color would it have seemed to you?
Physics
1 answer:
kykrilka [37]3 years ago
3 0

Answer

given,

wavelength of the red light,λ = 687 nm

wavelength of the yellow light = 582 nm

Frequency of red light

=\dfrac{v}{\lambda}

=\dfrac{3\times 10^8}{687\times 10^{-9}}

= 4.36 x 10¹⁴ Hz

frequency of the yellow light

=\dfrac{3\times 10^8}{582\times 10^{-9}}

= 5.15 x 10¹⁴ Hz

speed of the car

f = f_o(\dfrac{c+v_r}{c})

v_r is the required speed.

5.15\times 10^{14}=4.36\times 10^{14}(\dfrac{c+v_r}{c})

v_r = 0.19 c

v_r = 0.19 x 3 x 10⁸ =5.7 x 10⁷ m/s

1 m/s = 2.23694 mile/hr

v_r = 1.27 x 10⁸ mile/hr

if the light is actually yellow

f₀ = 5.15 x 10¹⁴ Hz

f =5.15\times 10^{14}(\dfrac{c+0.19c}{c})

f = 6.13 x 10¹⁴ Hz

wavelength corresponding to this frequency is wavelength = 493.2 nm

hence, the color corresponding to this wavelength is Green.

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because it’s suppose to be red like a stop light.

Explanation:

So it tells you to stop

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Two identical twins hold on to a rope, one at each end, on a smooth, frictionless ice surface. They skate in a circle about the
777dan777 [17]

Answer:

Part a)

L = 2683.2 kg m^2/s

Part b)

v' = 8.60 m/s

Part c)

W = 4326.7 J

Explanation:

Part a)

As we know that there is no external torque on the system of two twins

so here we will use

L = mv r + mvr

L = 2(78 \times 4.30 \times 4)

L = 2683.2 kg m^2/s

Part b)

Since angular momentum is conserved here as there is no external torque

so we will have

2(m v r) = 2( m v' \frac{r}{2})

v' = 2v

v' = 8.60 m/s

Part c)

Work done by both of them = change in kinetic energy

so we have

W = 2(\frac{1}{2}mv'^2 - \frac{1}{2}mv^2)

W = m(v'^2 - v^2)

W = 78(8.60^2 - 4.3^2)

W = 4326.7 J

5 0
3 years ago
4.
Pie

Answer:

b

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During physical activity of moderate intensity, your heart will beat at a percentage of its maximum rate. What is the target hea
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The target heart rate for moderate-intensity activity is 80%
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3 years ago
A 100.0 gram sample of Polonium-210 is contained for 552 days. How many half-lives occur during this period of time, if the half
Leto [7]

Answer:

4 half-lives will occur during this period of time.

Explanation:

Formula used :

a_o=a\times e^{-\lambda t}

\lambda =\frac{0.693}{t_{1/2}}

a=\frac{a_o}{2^n}

where,

a = amount of reactant left after n-half lives and time t

a_o = Initial amount of the reactant.

\lambda = decay constant

t_{1\2} = half life of an isotope

n = number of half lives

We have :

a_o=100.0 g

a = ?

t = 552 days

t_{1/2}=138 days

a=100.0 g\times e^{-\frac{0.693}{138}\times 552}

a=6.254 g

6.254 g=\frac{100.0 g}{2^n}

2^n=\frac{100.0 g}{6.254 g}

n = 4

4 half-lives will occur during this period of time.

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3 years ago
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