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goblinko [34]
3 years ago
12

A submarine is at an ocean depth of 3.00 km.

Physics
1 answer:
Alexxx [7]3 years ago
7 0

Answer:

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Water enters a baseboard radiator at 180 °F and at a flow rate of 2.0 gpm. Assuming the radiator releases heat into the room at
beks73 [17]

Answer:

Temperature of water leaving the radiator = 160°F

Explanation:

Heat released = (ṁcΔT)

Heat released = 20000 btu/hr = 5861.42 W

ṁ = mass flowrate = density × volumetric flow rate

Volumetric flowrate = 2 gallons/min = 0.000126 m³/s; density of water = 1000 kg/m³

ṁ = 1000 × 0.000126 = 0.126 kg/s

c = specific heat capacity for water = 4200 J/kg.K

H = ṁcΔT = 5861.42

ΔT = 5861.42/(0.126 × 4200) = 11.08 K = 11.08°C

And in change in temperature terms,

10°C= 18°F

11.08°C = 11.08 × 18/10 = 20°F

ΔT = T₁ - T₂

20 = 180 - T₂

T₂ = 160°F

8 0
3 years ago
A car starts moving from the position of rest with uniform acceleration of 8m/s^calculate the distance travelled by it during 10
ad-work [718]

We calculate the coordinates at t₁ = 9 min and t₂ = 10 min, since the 10th minute is between t₁ and t₂.

As it leaves from rest, it means that the initial speed is zero


t₁=9 min=540 s

t₂=10 min=600 s

x₁=at₁²/2=8*540²/2=4*291600=1166400 m

x₂=at₂²/2=8*600²/2=4*360000=1440000 m

Δx=x₂-x₁=1440000-1166400=273600 m represents the distance traveled by the car in the 10th minute of travel




8 0
3 years ago
Describe what happens when electrical impulses cross muscle fibers
kaheart [24]

Answer:

Sometimes may cause involuntary responses like twitching

Explanation:

8 0
3 years ago
Two thin conducting plates, each 56.0 cm on a side, are situated parallel to one another and 7.0 mm apart. If 10^-10 electrons a
dsp73

Answer:

E=576.5V/m

Explanation:

From the question we are told that:

Length l=56.0cm=0.56m

Distance apart d=7.0mm=0.007m

Electron Transferred n=10^{-10}

Therefore

Total Charge

Since Charge on each electron is

e=1.602*10^{-19}

Therefore

T=1.602*10^{-19} *10^{10}

T=1.602*10^{-9}

Generally the equation for Charge density is mathematically given by

\rho=T/A

Where

Area

A=0.56*0.56

A=0.3136

Therefore

\rho=1.602*10^{-9}/0.3136

\rho=5.10*10^{-9}

Generally the equation for Electric Field in the capacitor is mathematically given by

E=\frac{\rho}{e_0}

E=\frac{5.10*10^{-9}}{8.85x10{-12}}

E=576.5V/m

8 0
3 years ago
Which describes an image that a concave mirror can make? Which describes an image that a concave mirror can make?
Shkiper50 [21]

Answer:

the image can be rather real or virtual

3 0
3 years ago
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