3 x 10 to the sixth power
3 x 10 to the fifth power
7 x 10 to the fourth power
6 x 10 to the first power
I might be wrong though. If so, sorry!
Total spoon required is mentioned in the Attachment.
Step-by-step explanation:
- Clustered column bar graph used.
- each 18 milligrams divide by the data provided
- beef is blue label
- plant is orange labelled.
- Microsoft office used Iron,Calcium and Vitamins in column
- Microsoft office used Beef in one row.
- Microsoft office Plant used in 2nd row.
- Chart title, Axis title and design changed.
- Bar graph is better interpretation for three columns.
The weight loss in these three methods does not differ because the average weight loss is very similar in all 3.
<h3>How to calculate the average weight loss?</h3>
To calculate the average weight loss in these three situations, we must add all the values and divide the result by the number of values, for example:
- 7 + 7 + 5 + 4 + 6 = 29
- 7 + 8 + 8 + 9 + 5 = 37
- 7 + 9 + 7 + 8 + 8 = 39
- 39 ÷ 5 = 7.8
- 37 ÷ 5 = 7.4
- 29 ÷ 5 = 5.8
According to the above, it can be inferred that the hypothesis that the difference between one program and another is not significant enough to consider one plan more or less effective than another, because radically differences are not shown in each case.
Learn more about hypothesis in: brainly.com/question/2695653
Answer:
Step-by-step explanation:
Base + 4 triangles
(18.4)(27.6) + 2(½×27.7×17.6) + 2(½×18.4×20.4)
Answer:
Step-by-step explanation:
Here we are going to use the rule which says that
i) equal arc segments subtends equal angles at the circle
ii) The Angle subtended by any arc segment at center is double to that of the angle subtended by the same arc at its circumference.
For more details please refer to the image attached to this problem.
Let us say that the angle subtended by arc mAB at center O = 6∅
Hence , ∠AOB=6∅
Hence ∠ADB = 3∅ ( Rule ii as discussed above )
Also as length of arc mCD = x , the angle subtended by it on the center will be in the same ratio as it was subtended by arc with length 6x
Hence
∠COD=∅
Hence
∠CAD=∅/2
Hence in ΔATD
∠ATD + ∠ADT +∠DAT = 180°
∠ATD + 3∅+∅/2= 180°
∠ATD = 180° - (3∅+∅/2) ----------(A)
Also
∠ATD + ∠ATB = 180°
From (A)
180° - (3∅+∅/2) +∠ATB = 180°
∠ATB = (3∅+∅/2)
∠ATB = (6∅+∅)/2
∠ATB = (7∅)/2
However , in order to find the exact value of∠ATB we need to evaluate ∅, and to find it , we must have some value of x .