<h3>Conner work is correct. Jana work is wrong</h3>
<em><u>Solution:</u></em>
<em><u>Given that,</u></em>
<em><u>Conner and Jana are multiplying:</u></em>

Given Conner's work is:

We have to check if this work is correct
Yes, Conner work is correct
From given,

Use the following law of exponent

Therefore,

<em><u>Given Jana's work is:</u></em>

This is incorrect
The powers of same base has to be added. But here, powers are multiplied which is wrong
Answer:
b = 9 ft
Step-by-step explanation:
Pythagorean Theorem:
a^2 + b ^2 = c^2
Given:
a = 12
b = ?
c = 15
Plug in values:
12^2 + b^2 = 12^2
Solve for b^2:
b^2 = 15^2 - 12^2
b^2 = 225 - 144
b^2 = 81
Take square root of both sides to find b:
sqrt(b^2) = sqrt(81)
b = 9
Hope this helps! :)
4/25
Step-by-step explanation:
16/100, 8/50, 4/25
The answer is the answer is 21 sq in