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4 years ago

7

A student received a 75% on an exam. If there were 20 questions on the exam, which ratio would show the number of questions answ

ered correctly to the total number of questions?

1 answer:

madreJ [45]4 years ago

8 0

75% of 20 = 15
Required ratio is 15:20 which simplifies to 3:4.

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Plz help it's due till 12.06

larisa [96]

Answer:

4

Step-by-step explanation:

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3 years ago

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How do you determine the base when solving for x by converting to a log?

worty [1.4K]

$$x=\frac{\ln \left(\frac{3}{2}\right)}{4 \ln (1.0125)}$

Solution:

Given expression:

$$(1.0125)^{4 x}=\frac{3}{2}$

To solve the expression:

$$(1.0125)^{4 x}=\frac{3}{2}$

<em>If f(x) = g(x) then ln(f(x)) = ln(g(x)).</em>

Using the above condition, we can write

$$\ln \left(1.0125^{4 x}\right)=\ln \left(\frac{3}{2}\right)$

Apply log rule: $\log _{a}\left(x^{b}\right)=b \cdot \log _{a}(x)$

$$4 x \ln (1.0125)=\ln \left(\frac{3}{2}\right)$

Divide both side of the equation by $4 \ln (1.0125)$ .

$$\frac{4 x \ln (1.0125)}{4 \ln (1.0125)}=\frac{\ln \left(\frac{3}{2}\right)}{4 \ln (1.0125)}$

$$x=\frac{\ln \left(\frac{3}{2}\right)}{4 \ln (1.0125)}$

The answer is $x=\frac{\ln \left(\frac{3}{2}\right)}{4 \ln (1.0125)}$ .

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3 years ago

Find an input that yield an output of -1 rule y=-2x+33

djyliett [7]

Input (x-value)

Output (y-value)

You need to find the x-value that produces a y-value of -1. Since you know:

y = -1 Use the rule, and substitute/plug this into the equation

y = -2x + 33 Plug in -1 for "y" in the equation since y = -1

-1 = -2x + 33 Subtract 33 on both sides

-1 - 33 = -2x + 33 - 33

-34 = -2x Divide -2 on both sides to get "x" by itself

$\frac{-34}{-2}=\frac{-2x}{-2}$

17 = x

An input of 17 yields an output of -1

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3 years ago

Find a formula for the nth term of the arithmetic sequence:

Zolol [24]

-2\8 = a negative so we will multiply

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3 years ago

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Simplify (x − 4)(2x2 + 3x − 5).

xeze [42]

The simplified form of given expression is $2x^3-5x^2-17x+20$

<em><u>Solution:</u></em>

Given that we have to simplify the expression

<em><u>Given expression is:</u></em>

$(x-4)(2x^2+3x-5)$

We can simplify the expression by multiplying each term in first bracket with each term term in second bracket

$\rightarrow (x-4)(2x^2+3x-5)$

$\rightarrow (x)(2x^2)+(x)(3x)+(x)(-5)-4(2x^2)-4(3x)-4(-5)$

Simplify the above expression by multiplying the numbers in each term and adding the coefficients of like variables in each term

$\rightarrow 2x^3+3x^2-5x-8x^2-12x+20$

Combine the like terms

$\rightarrow 2x^3+3x^2-8x^2-5x-12x+20$

$\rightarrow 2x^3-5x^2-17x+20$

Thus the expression is simplified

5 0

3 years ago