
multiplying both sides by x^2

simplifying

dividing by 7
The second graph: y = 3
Domain: all real number
Range: y = 3
Answer:

Step-by-step explanation:
We can use the pascal triangle to find the coefficients of the expasion of the cube. It holds that

Answer:
is the root of 5 not equal why
The volume is 96.
v=l*w*h
v=6*3*3=54
v=2*3*7=42
54+42=96
Hope this helps