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Verizon [17]
3 years ago
13

If it snowed 6 inches on Friday and then 1/2 of that on Saturday, then on Sunday 1/3 of all of that, how much snow did we get al

l together?
Mathematics
1 answer:
Kryger [21]3 years ago
3 0

Answer:

Step-by-step explanation:

snowed

Friday=6 inches

Saturday=1/2×6=3 inches

Sunday=1/3(6+3)=1/3×9=3 inches

Total snow=6+3+3=12 inches

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Emilia conducted an experiment with Growing crystals. At the beginning of the experiment, she had a crystal that measured 6MM. S
hammer [34]

Answer: (2,30), (5,66)

Step-by-step explanation: I truly don’t know if this is correct, but at the beginning, the crystal was already 6 mm. She then realized it increased 12 mm every hour, so if one hour passed, it would be 12+6= 18. Okay, so now that we know that, we multiple the hours by 12 and then add the 6.

12x2= 24

24+ 6= 30,

12x5= 60

60+6= 66

6 0
3 years ago
Twice the diffrence of a number and 9 is equal to three times the sum of the number and 5. Find the number
Elan Coil [88]
2(n-9) = 3(n + 5)
2n - 18 = 3n + 15
2n - 3n = 15 + 18
-n = 33
n = -33
5 0
3 years ago
Simplify the expression <img src="https://tex.z-dn.net/?f=%5Cfrac%7B-5%2Bi%7D%7B2i%7D" id="TexFormula1" title="\frac{-5+i}{2i}"
Fudgin [204]

Answer:

1/2 + 5/2 i

Step-by-step explanation:

(-5+i)         i

---------* --------

2i             i

cannot have i in the denominator so we multiply by i

(-5+i)         i             -5i + i^2

---------* --------  = ----------------

2i             i              +2i^2

remember i^2 = -1

     -5i + -1        -1 -5i

= ---------------- = ------------------

    +2(-1)                        -2

get rid of the negative in the denominator by multiplying the top and bottom by -1

    (-1 -5i) * -1

= ------------------

          -2*(-1)


    (1 +5i)

= ------------------   =   1/2 + 5/2 i

          2

6 0
3 years ago
Please help i don't know
daser333 [38]

Answer:

the second one

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Angles α and β are angles in standard position such that: α terminates in Quadrant I and sinα = 3/5 β terminates in Quadrant III
Arte-miy333 [17]

Answer:

-16/65

Step-by-step explanation:

Given sinα = 3/5 in quadrant 1;

Since  sinα = opp/hyp

opp = 3

hyp = 5

adj^2 = hyp^2 - opp^2

adj^2 = 5^2 = 3^2

adj^2 = 25-9

adj^2 = 16

adj = 4

Since all the trig identity are positive in Quadrant 1, hence;

cosα = adj/hyp = 4/5

Similarly, if tanβ = 5/12 in Quadrant III,

According to trig identity

tan theta = opp/adj

opp = 5

adj = 12

hyp^2 = opp^2+adj^2

hyp^2 = 5^2+12^2

hyp^2 = 25+144

hyp^2 = 169

hyp = 13

Since only tan is positive in Quadrant III, then;

sinβ = -5/13

cosβ = -12/13

Get the required expression;

sin(α - β) = sinαcosβ - cosαsinβ

Substitute the given values

sin(α - β) = 3/5(-12/13) - 4/5(-5/13)

sin(α - β)= -36/65 + 20/65

sin(α - β) = -16/65

Hence the value of sin(α - β) is -16/65

5 0
3 years ago
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