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Fed [463]
3 years ago
9

jaylyn rode her bicycle in a bike-a-thon. she rode 33.48 miles in 2.7 hours. if she rode at the same speed, what was her speed i

n miles per hour?
Mathematics
2 answers:
mario62 [17]3 years ago
8 0
33.48 divided by 2.7 that will give you 12.4
r-ruslan [8.4K]3 years ago
8 0

Answer:

12.4\frac{miles}{hour}

Step-by-step explanation:

we know that

To find the speed divide the total distance by the total time

so

Let

x-----> the total distance in miles

y----> the total time in hours

s----> speed in miles per hours

s=\frac{x}{y}

we have

x=33.48\ miles

y=2.7\ hours

substitute the values

s=\frac{33.48}{2.7}=12.4\frac{miles}{hour}

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3 years ago
A triangle has height 15 in. and area 120 in. what is the lenght of its base?
nikklg [1K]
The base of the triangle measures 16 in.
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Factor completely.<br><br> x2+7x−18<br><br><br> Answer now PLZZZZZ
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Answer: ( − 2) ( + 9)

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Complete the assignment on a separate sheet of paper<br><br> Please attach pictures of your work.
Irina18 [472]

Answer:

<u>TO FIND :-</u>

  • Length of all missing sides.

<u>FORMULAES TO KNOW BEFORE SOLVING :-</u>

  • \sin \theta = \frac{Side \: opposite \: to \: \theta}{Hypotenuse}
  • \cos \theta = \frac{Side \: adjacent \: to \: \theta}{Hypotenuse}
  • \tan \theta = \frac{Side \: opposite \: to \: \theta}{Side \: adjacent \: to \: \theta}

<u>SOLUTION :-</u>

1) θ = 16°

Length of side opposite to θ = 7

Hypotenuse = x

=> \sin 16 = \frac{7}{x}

=> \frac{7}{x} = 0.27563......

=> x = \frac{7}{0.27563....} = 25.39568..... ≈ 25.3

2) θ = 29°

Length of side opposite to θ = 6

Hypotenuse = x

=> \sin 29 = \frac{6}{x}

=> \frac{6}{x} = 0.48480......

=> x = \frac{6}{0.48480....} = 12.37599..... ≈ 12.3

3) θ = 30°

Length of side opposite to θ = x

Hypotenuse = 11

=> \sin 30 = \frac{x}{11}

=> \frac{x}{11} = 0.5

=> x = 0.5 \times 11 = 5.5

4) θ = 43°

Length of side adjacent to θ = x

Hypotenuse = 12

=> \cos 43 = \frac{x}{12}

=> \frac{x}{12} = 0.73135......

=> x = 12 \times 0.73135.... = 8.77624.... ≈ 8.8

5) θ = 55°

Length of side adjacent to θ = x

Hypotenuse = 6

=> \cos 55 = \frac{x}{6}

=> \frac{x}{6} = 0.57357......

=> x = 6 \times 0.57357.... = 3.44145.... ≈ 3.4

6) θ = 73°

Length of side adjacent to θ = 8

Hypotenuse = x

=> \cos 73 = \frac{8}{x}

=> \frac{8}{x} = 0.29237......

=> x = \frac{8}{0.29237.....} = 27.36242..... ≈ 27.3

7) θ = 69°

Length of side opposite to θ = 12

Length of side adjacent to θ = x

=> \tan 69 = \frac{12}{x}

=> \frac{12}{x} = 2.60508......

=> x = \frac{12}{2.60508....}  = 4.60636.... ≈ 4.6

8) θ = 20°

Length of side opposite to θ = 11

Length of side adjacent to θ = x

=> \tan 20 = \frac{11}{x}

=> \frac{11}{x} = 0.36397......

=> x = \frac{11}{0.36397....}  =30.22225.... ≈ 30.2

5 0
3 years ago
Can someone answer this question please please help me I really need it if it’s correct I will mark you brainliest .
GenaCL600 [577]

Answer:∠KJG and ∠FGJ

Step-by-step explanation:

Alternate interior angles are diagonal from each other and are the same value.

4 0
3 years ago
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