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Vilka [71]
3 years ago
15

A place Or object used for comparison to determine if something is in motion is called a what?

Physics
1 answer:
TiliK225 [7]3 years ago
8 0

Answer:

\boxed{ \bold{ \sf{Reference \: point}}}

A place or object used for comparison to determine if something is in motion is called a <u>reference</u><u> </u><u>point</u><u> </u>.

✎ Explanation :

A reference point can be defined as a fixed point / place / object from which we compare the motion of an object. For example :

  • When we are travelling by bus , we are in motion with respect to a nearby tree. Here , the tree acts as a reference point or reference frame.

Hope I helped!

Have a wonderful time ツ

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Two wires are identical, except that one is aluminum and one is tungsten. the aluminum wire has a resistance of 0.22 ω. what is
Margaret [11]
The resistance R of a piece of wire is given by
R=\rho  \frac{L}{A}
where \rho is the resistivity of the material, L is the length of the wire and A is its cross-sectional area.

Using this formula, and labeling with A the aluminum and with T the tungsten wire, we can write the ratio between R_T (the resistance of the tungsten wire) and R_A (the resistance of the aluminum wire):
\frac{R_T}{R_A}= \frac{\rho_T  \frac{L}{A} }{\rho_A  \frac{L}{A} }

the two wires are identical, so L and A are the same for the two wires and simplify in the ratio, and we get:
R_T =  \frac{\rho_T}{\rho_A} R_A

By using the resistivity of the aluminum: \rho_A=2.65 \cdot 10^{-8} \Omega m and the resistivity of the tungsten: \rho_T = 5.6 \cdot 10^{-8} \Omega mm we can get the resistance of the tungsten wire:
R_T =  \frac{\rho_T}{\rho_A} R_A =   \frac{ 5.6 \cdot 10^{-8} \Omega m}{2.65 \cdot 10^{-8} \Omega m}   (0.22 \Omega) = 0.46 \Omega
5 0
3 years ago
A spring has a period of 1 s when a 0.200 kg mass hung from the end of it. If the mass at the end is changed to 0.100 kg, will t
shutvik [7]

When the mass of the spring changed from 0.2kg to 0.1kg, the time period changed from 1 sec to 0.5 seconds

<u>Explanation:</u>

Given-

Mass, m1 = 0.2kg

Time period, T1 = 1s

m2 = 0.1 kg

T2 = ?

We know,

T = 2\pi \sqrt{\frac{m}{k} }

where,

T = Time period

m = mass

k = spring constant

From the equation, we can see that T is directly proportion to the square root of mass, m

T ∝ √m

So,

If m1 = 0.2kg , T1 = 1s and m2 = 0.1kg

The T2 would be:

\frac{T1}{T2} = \frac{m1}{m2} \\\\\frac{1}{T2} = \frac{0.2}{0.1} \\

T2 = \frac{1}{2} \\\\T2 = 0.5sec

Therefore, when the mass of the spring changed from 0.2kg to 0.1kg, the time period changed from 1 sec to 0.5 seconds

3 0
3 years ago
The voltage or potential difference provides the ____ required for electrons to travel through a circuit
galben [10]

Answer:

a. push

Explanation:

Voltage is the force or pressure that is responsible for pushing the charge or electrons to flow in a closed-looped electrical circuit. This flow of electrons (charge) is called the electric current. It is also defined as the difference in electric potential per unit charge between two points in an electric field.

5 0
3 years ago
Three polarizing filters are stacked, with the polarizing axis ofthe second and third filters at angles of 22.2^\circ and 68.0^\
andreev551 [17]

Answer:

I₂ = 25.4 W

Explanation:

Polarization problems can be solved with the malus law

     I = I₀ cos² θ

Let's apply this formula to find the intendant intensity (Gone)

Second and third polarizer, at an angle between them is

    θ₂ = 68.0-22.2 = 45.8º

    I = I₂ cos² θ₂

    I₂ = I / cos₂ θ₂

    I₂ = 75.5 / cos² 45.8

    I₂ = 155.3 W

We repeat for First and second polarizer

   I₂ = I₁ cos² θ₁

   I₁ = I₂ / cos² θ₁

   I₁ = 155.3 / cos² 22.2

   I₁ = 181.2 W

Now we analyze the first polarizer with the incident light is not polarized only half of the light for the first polarized

    I₁ = I₀ / 2

   I₀ = 2 I₁

   I₀ = 2 181.2

   I₀ = 362.4 W

Now we remove the second polarizer the intensity that reaches the third polarizer is

    I₁ = 181.2 W

The intensity at the exit is

    I₂ = I₁ cos² θ₂

    I₂ = 181.2 cos² 68.0

   I₂ = 25.4 W

8 0
4 years ago
Three resistors with the values of R_1, R_2, and R_3 are connected in parallel. Which of the following expresses the total resis
bagirrra123 [75]

Answer: Option d.)

R_eq = (1/R_1 + 1/R_2 + 1/R_3)^-1

Explanation:

Since, there are three resistors connected in parallel, the reciprocal of the total resistance of the resistor combination (R_eq) is obtained by adding the reciprocal of each resistance.

i.e 1/R_eq = (1/R_1 + 1/R_2 + 1/R_3)

So, R_eq = (1/R_1 + 1/R_2 + 1/R_3)^-1

Thus, the total resistance (R_eq) is equal to the inverse of the sum of the reciprocal of each resistance.

3 0
4 years ago
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