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postnew [5]
3 years ago
15

If Earth was with no tilt, would we still have seasons at all? If so, how would they be different?

Physics
1 answer:
murzikaleks [220]3 years ago
8 0

Answer:

If earth had no tilt, we would have no seasons.

Explanation:

As stated in the answer, if the earth had no tilt we wouldn't have seasons. The earth all around the globe would maintain the same temperature,

And due to the no tilt it would also change our orbit to a bit larger slant, in January when we are at our closest to the sun we WOULD have a mini summer. For the North and South Pole, they would remain cold.

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The net force on the propeller of a 3.2 kg model airplane is 7.0N forward. What is the acceleration of the airplane? If it start
Korolek [52]

Answers:

Acceleration = 2.1875 m/s^2

Velocity after 2.5 seconds = 5.46875 m/s

=======================================================

Work Shown:

Part 1

The mass is m = 3.2 and the force is F = 7.0

Apply the formula F = ma to find the acceleration to be...

F = ma

7.0 = 3.2*a

7.0/3.2 = a

2.1875 = a

a = 2.1875

The acceleration is 2.1875 m/s^2

Every second, the velocity of the plane is increasing by 2.1875 m/s.

----------------------

Part 2

We have the following variables

  • vi = initial velocity = 0 m/s (since it starts from rest)
  • vf = unknown final velocity (what we're trying to figure out)
  • t = change in time = 2.5 seconds
  • a = acceleration = 2.1875 m/s^2

Using one of the kinematics equations, we can then say,

vf = vi + a*t

vf = 0 + 2.1875*2.5

vf = 5.46875

After 2.5 seconds, the airplane is traveling 5.46875 m/s.

5.46875 m/s converts to roughly 12.2332 mph.

6 0
2 years ago
Suppose you have a pendulum clock which keeps correct time on Earth(acceleration due to gravity = 1.6 m/s2). For ever hour inter
kaheart [24]

The moon clock is A) (9.8/1.6)h compared to 1 hour on Earth

Explanation:

The period of a simple pendulum is given by the equation

T=2\pi \sqrt{\frac{L}{g}}

where

L is the length of the pendulum

g is the acceleration of gravity

In this problem, we want to compare the period of the pendulum on Earth with its period on the Moon. The period of the pendulum on Earth is

T_e=2\pi \sqrt{\frac{L}{g_e}}

where

g_e = 9.8 m/s^2 is the acceleration of gravity on Earth

The period of the pendulum on the Moon is

T_m=2\pi \sqrt{\frac{L}{g_m}}

where

g_m = 1.6 m/s^2 is the acceleration of gravity on the Moon

Calculating the ratio of the period on the Moon to the period on the Earth, we find

\frac{T_m}{T_e}=\frac{g_e}{g_m}=\frac{9.8}{1.6}

Therefore, for every hour interval on Earth, the Moon clock will display a time of

A) (9.8/1.6)h

#LearnwithBrainly

6 0
3 years ago
A quantity of gas is contained in a sealed container of fixed volume. The temperature of the
Alchen [17]

Answer:

If the Kelvin temperature of a gas is increased, the volume of the gas increases. This can be understood by imagining the particles of gas in the container moving with a greater energy when the temperature is increased.

Explanation:

If you heat a gas you give the molecules more energy so they move faster. This means more impacts on the walls of the container and an increase in the pressure. Conversely if you cool the molecules down they will slow and the pressure will be decreased.

To calculate a change in pressure or temperature using Gay Lussac's Law.

6 0
3 years ago
A boy of mass, m weights 895 N. What is his mass, m?
Ksju [112]

Answer:

91.3 kg

Explanation:

weight = m*g

m: mass

g: gravity = 9.8 or 10 (depends on what your instructor tells you to use)

mass = w/g

895/9.8 = 91.3 KG

6 0
3 years ago
In 1993, Cuban athlete Javier Sotomayor set the world record for the high jump. The gravitational potential energy associated wi
Katarina [22]

Answer:2.541

Explanation:

Well , Potential Energy = mgh

m=mass = 82

g=acceleration of gravity=9.80m/s^2

h=what we are looking for

PE=mgh

PE/(mg) = h

Substitute in the values:

1970/(82 x 9.8) = h 2.541

5 0
3 years ago
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