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3 years ago

Please Help Me!!!........

Physics

1 answer:

nika2105 [10]3 years ago

8 0

Answer:

Hola, veo que quieres la respuesta, así que todo lo que tienes que hacer es traducir esto, EHHHHH me encontraste y la respuesta es un

Explanation:

ps this is a real answer

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In downtown Chicago, the east-west blocks are 400 ft long while the north-south blocks are 280 ft long. Because of the many one-

pickupchik [31]

Answer:

The answer is "1160 ft".

Explanation:

Using the Pythagoras theorem:

$\to a= 280 \times 3= 840\\\\\to b= 400 \times 2= 800\\\\$

$\bold{\to y^2= a^2+b^2}\\\\$

$=840^2 +800^2\\\\= 705600+640000\\\\=1345600\\\\=1160 \ ft\\$

$\to y=1160 \ ft$

8 0

3 years ago

before leaving earth, the mass if an astronaut is measured to be 60kg. the astronaut lands on the moon and measures the accelera

Nadya [2.5K]

Answer:

The answer is 2,475$+948= add you will get the answer rn

3 0

3 years ago

When does the difference between two vectors equal to zero ?

SVEN [57.7K]

Answer: Yes, two vectors of equal magnitude that are pointing in opposite directions will sum to zero

Explanation: Two vectors of unequal magnitude can never sum to zero. If they point along the same line, since their magnitudes are different, the sum will not be zero.

5 0

3 years ago

Calculate the amount of work done if you use a 100 N force to push a 50 kg box 5 m across the kitchen floor.

gogolik [260]

Work = force * distance
force = 100 N
Distance = 5m
work =100 N* 5m
=500 J

3 0

3 years ago

Read 2 more answers

The only force acting on a 3.2 kg canister that is moving in an xy plane has a magnitude of 6.7 N. The canister initially has a

Fynjy0 [20]

Answer:

The work done by the force is 5.76 J

Explanation:

Given;

mass of canister , m = 3.2 kg

magnitude of force, f = 6.7 N

initial velocity of the canister on x-axis, $v_i$ = 3.3i m/s

final velocity of the canister on y- axis, $v_f$ = 6.9j m/s

The work done on the canister = change in the kinetic energy of the canister

$W = K.E_f - K.E_i$

where;

K.Ei is the initial kinetic energy

K.Ef is the final kinetic energy

The initial kinetic energy:

$K.E_i = \frac{1}{2} *m\sqrt{i^2 +j^2+z^2}\\\\K.E_i = \frac{1}{2} *3.2\sqrt{3.3^2 +0^2+0^2}\\\\K.E_i = 5.28 \ J$

The final kinetic energy:

$K.E_f = \frac{1}{2} *m\sqrt{i^2 +j^2+z^2}\\\\K.E_f = \frac{1}{2} *3.2\sqrt{0^2 +6.9^2+0^2}\\\\K.E_f = 11.04 \ J\\$

W = 11.04 - 5.28

W = 5.76 J

Therefore, work done on the canister by the 6.7 N force during this time is 5.76 J

3 0

3 years ago

Please Help Me!!!........​

Please Help Me!!!........