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3 years ago

Most of the water used in the United States and Canada is for residential use. Rue or false

Physics

1 answer:

Lady_Fox [76]3 years ago

5 0

The answer to this question is true

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A 1.0 kg object is attached to a string 0.50 m. It is twirled in a horizontal circle above the ground at a speed of 5.0 m/s. A b

aivan3 [116]

<span>50 N The centripetal force upon an object is expressed as F = mv^2/r So let's substitute the known values and calculate F = mv^2/r F = 1.0 kg * (5.0 m/s)^2 / 0.5 m F = 1.0 kg * 25 m^2/s^2 / 0.5 m F = 25 kg*m^2/s^2 / 0.5 m F = 50 kg*m/s^2 F = 50 N So the answer is 50 N which matches one of the available choices.</span>

6 0

3 years ago

An electrical drill has 100 J of chemical energy. Of the 100 J, 45 J are transformed into kinetic energy and 20 J are transforme

Rainbow [258]

The answer to this question is the thermal energy of the drill is 35 J

4 0

3 years ago

Read 2 more answers

A rock falls for 1.43 seconds how far did it fall? The falls's velocity is an acceleration of -9.81 m/s2

BartSMP [9]

Answer:

$s = -0.100 \ m$

Explanation:

Generally from kinematics equations we have that

$s = ut + \frac{1}{2}gt^2$

Here u is the initial velocity of the rock and the value is 0 m/s given that there was no information that it was in motion before the fall

substituting 1.43 s for t and $-9.8m/s^2$ for g we have that

$s = 0 *1.43 + \frac{1}{2}(-9.8)*(0.143)^2$

=> $s = -0.100 \ m$

The negative sign show that the displacement is in the direction of the negative y-axis

7 0

3 years ago

The time taken for an object to fall from a height of h m from the earth'fs surface is t s.

telo118 [61]

Answer:

B. Longer than t s,

Explanation:

Gravitational accln on earth is 9.8 m/s^2,

and one you provided as on moon is 1.6 m/s^2

that mean on moon gr. accl. is lesser!

now the time taken on earth will be lesser cuz from the same height if you drop the object from rest!

since accln on earth is higher,the object will attain higher velocity as compare to that of on moon!

✌️:)

6 0

3 years ago

Assuming no friction, how does the initial gravitational potential energy of

babymother [125]

Answer:

a) They are the same.

Explanation:

Assuming no friction, there should be no energy transfer and thus the Law of Conservation of Energy says:

$PE=KE,\\mgh=\frac{1}{2}mv^2$

These types of problems also disregard any air resistance the surface of the object may cause. Therefore, no energy is transferred and from the Law of Conservation of Energy, $100\%$ of energy is preserved.

5 0

3 years ago