Answer: 20 fragments
Explanation:
This particular restriction enzyme has a 4 bp (base pair) recognition sequence therefore it will cleave once every 4ⁿ bases where n indicates the number pf bases in the recognition sequence.
- The recognition sequence is 4 bp therefore this restriction enzyme cleaves once every 4⁴ = 256 bases. This is the length of the restriction fragment.
- Calculate the number of fragments by dividing the total number of bases ( where you assume equal frequency of bases ie. A+T = C+G) by the length of the restriction base.
- therefore 5000bp/256bp = <u>19,53</u> now this number ca n be rounded up to 20.
- The expected number of fragments on the electrophoresis gel will be 20 fragments.
Answer:
It will boil and become a gas
Explanation:
The plant and animal cell
I think the best answer is D
A, c, b i think. good luck!