A particle moves along the x-axis with velocity v(t) = t2 - 1, with t measured in seconds and v(t) measured in feet per second. find the total distance travelled by the particle from t = 0 to t = 2 seconds. 0.667 4 none of these 2
2 answers:
Answer:
0.667 feet
Step-by-step explanation:
To get the total distance travelled, we would integrate the velocity v(t) equation with respect to time t.
Given that the particle moves from t = 0 to t = 2 seconds
Integrating v(t) = t2 - 1
we get
= t^3/3 - t
substituting the boundaries from t = 0 to t = 2 seconds, we get
= 2^3/3 - 2 - (0^3/3 - 0)
= 8/3 - 2 - 0
= 0.667 feet
Answer:
help me plzz
Step-by-step explanation:
The velocity of a particle moving along the x-axis is v(t) = cos(2t), with t measured in minutes and v(t) measured in feet per minute. To the nearest foot find the total distance travelled by the particle from t = 0 to t = π minutes
You might be interested in
<span> y+15.5=|x|
The answer is SSA, that what I found
Of course, they are not equivalent.
Y-y1=m(x-x1)
Answer:
315
Step-by-step explanation:
because 15% of 2,100 is 315
