A particle moves along the x-axis with velocity v(t) = t2 - 1, with t measured in seconds and v(t) measured in feet per second. find the total distance travelled by the particle from t = 0 to t = 2 seconds. 0.667 4 none of these 2
2 answers:
Answer:
0.667 feet
Step-by-step explanation:
To get the total distance travelled, we would integrate the velocity v(t) equation with respect to time t.
Given that the particle moves from t = 0 to t = 2 seconds
Integrating v(t) = t2 - 1
we get
= t^3/3 - t
substituting the boundaries from t = 0 to t = 2 seconds, we get
= 2^3/3 - 2 - (0^3/3 - 0)
= 8/3 - 2 - 0
= 0.667 feet
Answer:
help me plzz
Step-by-step explanation:
The velocity of a particle moving along the x-axis is v(t) = cos(2t), with t measured in minutes and v(t) measured in feet per minute. To the nearest foot find the total distance travelled by the particle from t = 0 to t = π minutes
You might be interested in
Answer:
$.46 or 46 cents per foot
Step-by-step explanation:
3 yards = 4.14
1 yard is 3 feet
3 yards is 9 feet
4.14 ÷ 9 = .46
1.5 is lesser than 0.5. Oh, wait nevermind I meant to say -1.5 is lesser than 0.5
y=70(vertically opposite angle)
70+50+X =180 (sum of angles in triangles)
120+x=180
X=60 //
Answer:
the answer is 12x2 mskksksns
Answer:
Step-by-step explanation:
Area = 84sqaure inch
Width = 2 1/2inch = 5/2inch
Area = l × width
So: 84 = l × 5/2
168 = 5l
l =>168/5
l = 33 3/5