Let the 3 numbers be x and y and z. x + y + z = 24; 2x = z - 2; z = x + y. Change equations to:
(1) x + y + z = 24;(2) 2x - z = -2;(3) x + y - z = 0. Add equation 1 to equation 3: (4) 2x + 2y = 24. Add equation 1 to equation 2: (5) 3x + y = 22. Multiply equation 4 by 3: (6) 6x + 6y = 72. Multiply equation 5 by 2: (7) 6x+2y = 44.
Subtract equation 7 from equation 6: 4y = 28, then y = 7. Substitute y=7 to equation 6: 6x + 6(7) = 72, 6x + 42 = 72,
6x = 30, x = 5. Substitute x=5 and y=7 into equation 1: 5 + 7 + z = 24; 12 + z = 24; z = 12.
check: 5 + 7 + 12 = 24; 2(5)= 12-2 = 10; 12 = 7 + 5.
Answer:
= n - 2
Step-by-step explanation:
Note the difference between consecutive terms is constant, that is
0 - (- 1) = 0 + 1 = 1
1 - 0 = 1
2 - 1 = 1
3 - 2 = 1
This indicates the sequence is arithmetic with n th term
= a₁ + (n - 1)d
where a₁ is the first term and d the common difference
Here a₁ = - 1 and d = 1, thus
= - 1 + n - 1 = n - 2
