To look for the acceleration, it will come from:
vf^2=v0^2+2ad
where:
vf = final velocity = 0
v0 = initial velocity =251 m/s
a = acceleration
d= distance traveled = 0.237 m
0=251^2+2a(0.237 )
a= -251 ^2 / (2*0.237) =-132 913.502 m/s/s
we find the force from:
F = ma = 0.0115kg*(-1.32x10^5m/s/s) = -1518 N
the negative sign shows that the force is in the direction contradictory the
bullet's motion
Explanation:
At maximum height, the vertical component of a ball's speed is 0. So the net speed is equal to whatever the horizontal component of the ball is. If the ball is launched straight up, the speed at the highest point is simply 0.
Answer:
In the light bulb, the flow of charge through the filament heats it up and causes it to glow. In this way, the light bulb converts electrical energy to heat energy and light energy.
Explanation:
In the light bulb, the flow of charge through the filament heats it up and causes it to glow. In this way, the light bulb converts electrical energy to heat energy and light energy.
Answer:
Explanation:
The vertical component of velocity remains same as the free fall. The vertical motion of the projectile is same as the free fall motion.
Answer:
a)
v = 14.1028 m/s
∅ = 83.0765° north of east
b)
the required distance is 40.98 m
Explanation:
Given that;
velocity of the river u = 1.70 m/s
velocity of boat v = 14.0 m/s
Now to get the velocity of the boat relative to shore;
( north of east), we say
a² + b² = c²
(1.70)² + (14.0)² = c²
2.89 + 196 = c²
198.89 = c²
c = √198.89
c = 14.1028 m/s
tan∅ = v/u = 14 / 1.7 = 8.23529
∅ = tan⁻¹ ( 8.23529 ) = 83.0765° north of east
Therefore, the velocity of the boat relative to shore is;
v = 14.1028 m/s
∅ = 83.0765° north of east
b)
width of river = 340 m,
ow far downstream has the boat moved by the time it reaches the north shore in meters = ?
we say;
340sin( 90° - 83.0765°)
⇒ 340sin( 6.9235°)
= 40.98 m
Therefore, the required distance is 40.98 m
